五周期双覆盖和最短周期覆盖

Pub Date : 2024-08-12 DOI:10.1002/jgt.23164
Siyan Liu, Rong‐Xia Hao, Rong Luo, Cun‐Quan Zhang
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引用次数: 0

摘要

5-偶数子图循环双覆盖猜想(5-CDC 猜想)断言每个无桥图都有一个 5-偶数子图双覆盖。一个图的最短偶数子图盖是偶数子图族,它们覆盖了图的所有边,并且它们的长度之和最小。有人猜想,每个无桥图都有一个总长度至多为 的偶数子图盖。在本文中,我们研究了弱奇数 2 立方图的这两个猜想,并提出了此类图具有包含一个有多个顶点的成员的 5-CDC 的充分条件。作为推论,我们证明了满足充分条件的每个奇度为 2 的立方图都有一个总长度最多为 .我们还证明,每个周长至少为 30 的奇度为 2 的立方图都有一个包含至少一个长度为 的成员的 5-CDC ,因此它有一个总长度至多为 的 4-even 子图-覆盖。
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Five‐cycle double cover and shortest cycle cover
The 5‐even subgraph cycle double cover conjecture (5‐CDC conjecture) asserts that every bridgeless graph has a 5‐even subgraph double cover. A shortest even subgraph cover of a graph is a family of even subgraphs which cover all the edges of and the sum of their lengths is minimum. It is conjectured that every bridgeless graph has an even subgraph cover with total length at most . In this paper, we study those two conjectures for weak oddness 2 cubic graphs and present a sufficient condition for such graphs to have a 5‐CDC containing a member with many vertices. As a corollary, we show that for every oddness 2 cubic graph satisfying the sufficient condition has a 4‐even subgraph ‐cover with total length at most . We also show that every oddness 2 cubic graph with girth at least 30 has a 5‐CDC containing a member of length at least and thus it has a 4‐even subgraph ‐cover with total length at most .
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