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引用次数: 2
摘要
有一个源s(t),一个干扰j(t),两个输出xl(t)和xl(t)。信道系数h,既不知道,也不能通过通常的技术来识别,因为干扰与信号不协调。我们研究了两种信道容量:C,当j(t)为高斯时的Shannon容量;和C ?, j (t) = 0时的最优信道容量。我们首先证明了香农容量C可以通过盲技术实现。最优信道容量C可以吗?即使j (t) f O?如果是这样,当j(t) f 0时,香农容量将被打破,因为C' 7c。我们将证明在输出中有足够的信息可以实现C'。最新的调查结果将在会议上提出。
There are one source s(t), one jammingj(t), and two outputs xl( t ) and xl ( t ) . The channel coefficients h, are neither known, nor can be identified by usual techniques because the jamming is uncoordinated with the signal. We study two channel capacities: C, the Shannon capacity whenj(t) is Gaussian; and C?, the optimal channel capacity when j ( t ) = 0. We first show that the Shannon capacity C can be achieved by a blind technique. Can the optimal channel capacity C? be achieved even when j ( t ) f O? If so, the Shannon capacity will be broken because C' 7 C whenj(t) f 0. We will show that there is sufficient information in the output from which C' can be achieved. The latest findings will be presented at the Conference.