极值分析法估计最大裂纹长度时的合适样本面积和分区数:与分布形式无关的估计精度的评价

T. Matsumura, M. Ichikawa
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引用次数: 0

摘要

估计最大裂缝长度的统计结构组件的极端,一个遇到问题如何选择样本区域的年代(样本面积比整个区域)和部门的数量。在之前的论文,目前作者表明,均方根误差的估计价值,√V (X max)可以用一个线性函数近似情况下个人的日志年代裂纹长度遵循一个指数分布。本文通过理论分析和蒙特卡罗模拟,证明了√V(X max)/σ可以近似为log T的线性函数,而不管单个裂纹长度的分布形式如何,其中a为各元素区域最大裂纹长度所遵循的双指数分布的标准差,T(= m/S)为回归期。通过蒙特卡罗模拟得到的√V(X max)/σ比理论分析得到的大1.1 ~ 1.9倍。讨论了造成这种差异的原因。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
Suitable sample area and number of divisions in the estimation of the maximum crack length by extreme value analysis: Evaluation of estimation accuracy independent of distribution forms
In estimating the maximum crack length in a structural component by statistics of extremes, one encounters the problem of how to choose the sample area S (the ratio of the sample area to the whole area) and the number of divisions m. In a previous paper, the present authors showed that the root-mean-square error of the estimated value, √V(X max ) can be approximated by a linear function of log S for the case where individual crack lengths follow an exponential distribution. In the present paper, by conducting a theoretical analysis and Monte Carlo simulation, it is shown that √V(X max )/σ can be approximated by a linear function of log T regardless of the distribution forms of individual crack lengths, where a is the standard deviation of the double exponential distribution which the largest crack length in each elemental area follows, and T(= m/S) is the return period. It is also shown that √V(X max )/σ by Monte Carlo simulation is 1.1 to 1.9 times larger than that calculated by theoretical analysis. Causes for this difference are discussed.
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