一个极小极大交集问题

P. R. Meyers
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引用次数: 0

摘要

几年前,国家统计局的同事S. Haber提出了以下问题:选取n个单位区间的子集,每个子集的均值为112,因此求这些子集的两两积分截面的测度的最大值最小。该问题由Gilli的论文[1]1提出,该问题解决了“一个未发表的Erdos的假设”。证明了对于测度集合a的可枚举无穷集合,最大两两积分截面测度所对应的值有最小a 2•(具有更高的跨界基数e的集合由Gillis在[2]中处理。)在这里,我们提供了有限基数n的集合的显式解。进一步,也对应于[1],我们也考虑了与2 Sop Son的p-fold交集的情况,并提供了相应的显式解。(如[2]中所述,[1]的论证可以很容易地推广s,以证明aT'是可数无穷集合的极限值。)首先,我们引入了第二次最小化,并指出了它与极大极小问题的关系,即:选择n个子集a 10 A2,•。, A的单位积分的1/,每个h的测度A,使其p倍积分的和最小。如果现在X = {Slo . . "对于这个最小问题m的一个解,可以选择n,使得它的p折交集具有相同的测度s,如果m是任意集合a到a2的p折交集的测度的最大值,,“A n与所有fL(A J = A,那么
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A minimax-measure intersection problem
Some years ago, NBS colleague S. Haber communicated the following proble m: To select n subsets of the unit interval, each of mea sw'e 112, so a s to minimize the maximum of the measures of the pairwise inte rsections of these subse ts. The problem is suggested by a paper [1]1 of Gilli s which, settling "an unpubli shed conjec ture of Erdos," proves that for denumerably infinite collections of sets of measure a, the value corresponding to the maximum pairwise-inte rsection meas ure has infimum a 2 • (Collections with higher transfinit e cardinality are treated by Gillis in [2].) Here we provide an explicit solution for collections of finite cardinalities n. Further, and also corresponding to [1], we consider as well the case of p-fold intersections with 2 Sop Son, and provide the corresponding explicit solution. (As noted in [2], the argument of [1] easily extend s to show that aT' is the limiting value for a denumerably infinite collection.) As preliminary, we introduce a second minimization and point out its relationship to our minimax problem, to wit: Select n subsets A 10 A2 , • . , A 1/ of the unit inte rval, eac h of measure a, so that the sum of the measures of their p-fold inte rsections is minimum. If now X = {Slo . . " SI/}' a solution to this minimum proble m, can be chose n so that aU its p-fold intersections have the same measure s, and if M is the maximum of the measures of the p-fold intersections of an arbitrary collection A to A 2, . , " A n with all fL(A J = a, then
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