{"title":"匹克定理的新证明","authors":"S. Minsker","doi":"10.6028/jres.078b.014","DOIUrl":null,"url":null,"abstract":"f3 real. (See, for instance, [1], p. 224, ex. 4.) We offer the following proof whic h, although it also uses Bieberbach's result, is considerably different. PROOF: Let cP (z) J~ . Then cP sends the open unit disk into itself. Let cP 1= cP and inductively 1 a? define cPn=cP OcPlI t. If cPll(Z)=An,1 z+AIl,z Z2+ . .. ,it is clear that A\"'=M' A I ,2= M' AII ,I = A\", AIl I,t, and A II ,2 = AI ,I A nI,2 + A I,2 A;' _1.1' It follows that An,1 = A;'., and A II ,2 =A I ,zA :' ,-; 1 (l +A 1 , 1 +ALI + . . +A :',-;1). Now cPli/A 11 , 1 E!F for each n, so Bieberbach's theorem implies that IA\" ,2/A\" ,11 :s;: 2, or","PeriodicalId":166823,"journal":{"name":"Journal of Research of the National Bureau of Standards, Section B: Mathematical Sciences","volume":"27 1","pages":"0"},"PeriodicalIF":0.0000,"publicationDate":"1974-04-01","publicationTypes":"Journal Article","fieldsOfStudy":null,"isOpenAccess":false,"openAccessPdf":"","citationCount":"0","resultStr":"{\"title\":\"A new proof of pick's theorem\",\"authors\":\"S. Minsker\",\"doi\":\"10.6028/jres.078b.014\",\"DOIUrl\":null,\"url\":null,\"abstract\":\"f3 real. (See, for instance, [1], p. 224, ex. 4.) We offer the following proof whic h, although it also uses Bieberbach's result, is considerably different. PROOF: Let cP (z) J~ . Then cP sends the open unit disk into itself. Let cP 1= cP and inductively 1 a? define cPn=cP OcPlI t. If cPll(Z)=An,1 z+AIl,z Z2+ . .. ,it is clear that A\\\"'=M' A I ,2= M' AII ,I = A\\\", AIl I,t, and A II ,2 = AI ,I A nI,2 + A I,2 A;' _1.1' It follows that An,1 = A;'., and A II ,2 =A I ,zA :' ,-; 1 (l +A 1 , 1 +ALI + . . +A :',-;1). Now cPli/A 11 , 1 E!F for each n, so Bieberbach's theorem implies that IA\\\" ,2/A\\\" ,11 :s;: 2, or\",\"PeriodicalId\":166823,\"journal\":{\"name\":\"Journal of Research of the National Bureau of Standards, Section B: Mathematical Sciences\",\"volume\":\"27 1\",\"pages\":\"0\"},\"PeriodicalIF\":0.0000,\"publicationDate\":\"1974-04-01\",\"publicationTypes\":\"Journal Article\",\"fieldsOfStudy\":null,\"isOpenAccess\":false,\"openAccessPdf\":\"\",\"citationCount\":\"0\",\"resultStr\":null,\"platform\":\"Semanticscholar\",\"paperid\":null,\"PeriodicalName\":\"Journal of Research of the National Bureau of Standards, Section B: Mathematical Sciences\",\"FirstCategoryId\":\"1085\",\"ListUrlMain\":\"https://doi.org/10.6028/jres.078b.014\",\"RegionNum\":0,\"RegionCategory\":null,\"ArticlePicture\":[],\"TitleCN\":null,\"AbstractTextCN\":null,\"PMCID\":null,\"EPubDate\":\"\",\"PubModel\":\"\",\"JCR\":\"\",\"JCRName\":\"\",\"Score\":null,\"Total\":0}","platform":"Semanticscholar","paperid":null,"PeriodicalName":"Journal of Research of the National Bureau of Standards, Section B: Mathematical Sciences","FirstCategoryId":"1085","ListUrlMain":"https://doi.org/10.6028/jres.078b.014","RegionNum":0,"RegionCategory":null,"ArticlePicture":[],"TitleCN":null,"AbstractTextCN":null,"PMCID":null,"EPubDate":"","PubModel":"","JCR":"","JCRName":"","Score":null,"Total":0}
f3 real. (See, for instance, [1], p. 224, ex. 4.) We offer the following proof whic h, although it also uses Bieberbach's result, is considerably different. PROOF: Let cP (z) J~ . Then cP sends the open unit disk into itself. Let cP 1= cP and inductively 1 a? define cPn=cP OcPlI t. If cPll(Z)=An,1 z+AIl,z Z2+ . .. ,it is clear that A"'=M' A I ,2= M' AII ,I = A", AIl I,t, and A II ,2 = AI ,I A nI,2 + A I,2 A;' _1.1' It follows that An,1 = A;'., and A II ,2 =A I ,zA :' ,-; 1 (l +A 1 , 1 +ALI + . . +A :',-;1). Now cPli/A 11 , 1 E!F for each n, so Bieberbach's theorem implies that IA" ,2/A" ,11 :s;: 2, or