On generations by conjugate elements in almost simple groups with socle 2𝐹4(𝑞2)′

Pub Date : 2022-12-28 DOI:10.1515/jgth-2022-0216
D. Revin, A. Zavarnitsine
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Abstract

Abstract We prove that if L = F 4 2 ⁢ ( 2 2 ⁢ n + 1 ) ′ L={}^{2}F_{4}(2^{2n+1})^{\prime} and 𝑥 is a nonidentity automorphism of 𝐿, then G = ⟨ L , x ⟩ G=\langle L,x\rangle has four elements conjugate to 𝑥 that generate 𝐺. This result is used to study the following conjecture about the 𝜋-radical of a finite group. Let 𝜋 be a proper subset of the set of all primes and let 𝑟 be the least prime not belonging to 𝜋. Set m = r m=r if r = 2 r=2 or 3 and m = r − 1 m=r-1 if r ⩾ 5 r\geqslant 5 . Supposedly, an element 𝑥 of a finite group 𝐺 is contained in the 𝜋-radical O π ⁡ ( G ) \operatorname{O}_{\pi}(G) if and only if every 𝑚 conjugates of 𝑥 generate a 𝜋-subgroup. Based on the results of this and previous papers, the conjecture is confirmed for all finite groups whose every nonabelian composition factor is isomorphic to a sporadic, alternating, linear, unitary simple group, or to one of the groups of type B 2 2 ⁢ ( 2 2 ⁢ n + 1 ) {}^{2}B_{2}(2^{2n+1}) , G 2 2 ⁢ ( 3 2 ⁢ n + 1 ) {}^{2}G_{2}(3^{2n+1}) , F 4 2 ⁢ ( 2 2 ⁢ n + 1 ) ′ {}^{2}F_{4}(2^{2n+1})^{\prime} , G 2 ⁢ ( q ) G_{2}(q) , or D 4 3 ⁢ ( q ) {}^{3}D_{4}(q) .
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近似单群共轭元的代论(2)𝐹4(𝑞2)
摘要证明了若L= F 4 2 (22 2 n + 1) ' L={}^{2}f_{4}(2^{2n+1})^{\prime} 并且s1是𝐿的非恒等自同构,则G=⟨L, x⟩G=\langle L,x\rangle 有四个元素共轭到1,生成𝐺。利用这一结果研究了有限群的𝜋-radical的猜想。设0是所有素数集合的一个固有子集,设𝑟是不属于0的最小素数。设m=r,如果r=2,则设m=r,如果r=2或3,则设m=r−1,如果r小于5 r,则设m=r = 1\geqslant 5 . 假设,一个有限群𝐺的元素≥1包含在𝜋-radical O π (G) \operatorname{O}_{\pi}(G)当且仅当所有的𝑚共轭式都产生𝜋-subgroup。基于本论文和前几篇论文的结果,对于所有非贝尔组成因子同构于一个偶发的、交替的、线性的、酉的单群或B型群中的一个22²(22²²n + 1)的有限群,证实了这个猜想。 {}^{2}b……{2}(2^{2n+1}), g22减去(32减去n + 1) {}^{2}g_{2}(3^{2n+1}), f42减去(22减去n + 1) {}^{2}f_{4}(2^{2n+1})^{\prime} , g2∑(q) G_{2}(q)或者d43∑(q) {}^{3.}d_{4}(q)。
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