CHARACTER STACKS ARE PORC COUNT

IF 0.5 4区 数学 Q3 MATHEMATICS
Nick Bridger, Masoud Kamgarpour
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引用次数: 3

Abstract

We compute the number of points over finite fields of the character stack associated to a compact surface group and a reductive group with connected centre. We find that the answer is a polynomial on residue classes (PORC). The key ingredients in the proof are Lusztig’s Jordan decomposition of complex characters of finite reductive groups and Deriziotis’s results on their genus numbers. As a consequence of our main theorem, we obtain an expression for the E-polynomial of the character stack.
角色堆叠是porc计数
我们计算了与紧曲面群和中心连通的约化群相关的字符堆栈的有限域上的点数。我们发现答案是一个关于剩余类(PORC)的多项式。证明的关键成分是有限约化群复性质的Lusztig Jordan分解和Deriziotis关于它们的属数的结果。作为主要定理的结果,我们得到了字符栈e -多项式的表达式。
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来源期刊
CiteScore
1.70
自引率
0.00%
发文量
36
审稿时长
6 months
期刊介绍: The Journal of the Australian Mathematical Society is the oldest journal of the Society, and is well established in its coverage of all areas of pure mathematics and mathematical statistics. It seeks to publish original high-quality articles of moderate length that will attract wide interest. Papers are carefully reviewed, and those with good introductions explaining the meaning and value of the results are preferred. Published Bi-monthly Published for the Australian Mathematical Society
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