{"title":"Explicit discriminant and integral basis of \\({{\\textbf{Q}}}(\\root p^2 \\of {a})\\)","authors":"Anuj Jakhar","doi":"10.1007/s10474-026-01598-8","DOIUrl":null,"url":null,"abstract":"<div><p>Let <span>\\(K = {{\\textbf{Q}}}(\\theta )\\)</span> be an algebraic number field, where <span>\\(\\theta \\)</span> is a root of the irreducible polynomial <span>\\(x^n - a \\in {{\\textbf{Q}}}[x]\\)</span> of degree <i>n</i>, and let <span>\\({\\textbf {Z}}_K\\)</span> denote the ring of integers of <i>K</i>. In general, for arbitrary integers <i>n</i> and <i>a</i>, the explicit computation of the discriminant and an integral basis of <i>K</i> remains unresolved, except in special cases such as <span>\\(n = 4\\)</span>, 8, 9, a prime <i>p</i>, or a product <i>pq</i> of distinct primes <i>p</i> and <i>q</i>. Most existing results assume either that <i>a</i> is square-free or that <span>\\(\\gcd (a, n) = 1\\)</span>. In this article, we address the case <span>\\(n = p^2\\)</span> for an odd prime <i>p</i>, without imposing any condition on <i>a</i>. Using the theory of Newton polygons of first and second order, we determine the exact power of each prime <i>q</i> dividing the index <span>\\([{\\textbf {Z}}_K : {\\textbf {Z}}[\\theta ]]\\)</span>. This allows us to construct explicitly a <i>q</i>-integral basis of <i>K</i> for each prime <i>q</i>, which in turn yields a complete integral basis of <i>K</i>. Several illustrative examples are provided. As an application, we show that if <i>a</i> is square-free and satisfies <span>\\(a^{p-1} \\not \\equiv 1 \\pmod {p^2}\\)</span>, then <i>K</i> admits a power basis; that is, <span>\\({\\textbf {Z}}_K = {\\textbf {Z}}[\\theta ]\\)</span>.</p></div>","PeriodicalId":50894,"journal":{"name":"Acta Mathematica Hungarica","volume":"178 1","pages":"169 - 192"},"PeriodicalIF":0.6000,"publicationDate":"2026-05-04","publicationTypes":"Journal Article","fieldsOfStudy":null,"isOpenAccess":false,"openAccessPdf":"","citationCount":"0","resultStr":null,"platform":"Semanticscholar","paperid":null,"PeriodicalName":"Acta Mathematica Hungarica","FirstCategoryId":"100","ListUrlMain":"https://link.springer.com/article/10.1007/s10474-026-01598-8","RegionNum":3,"RegionCategory":"数学","ArticlePicture":[],"TitleCN":null,"AbstractTextCN":null,"PMCID":null,"EPubDate":"","PubModel":"","JCR":"Q3","JCRName":"MATHEMATICS","Score":null,"Total":0}
引用次数: 0
Abstract
Let \(K = {{\textbf{Q}}}(\theta )\) be an algebraic number field, where \(\theta \) is a root of the irreducible polynomial \(x^n - a \in {{\textbf{Q}}}[x]\) of degree n, and let \({\textbf {Z}}_K\) denote the ring of integers of K. In general, for arbitrary integers n and a, the explicit computation of the discriminant and an integral basis of K remains unresolved, except in special cases such as \(n = 4\), 8, 9, a prime p, or a product pq of distinct primes p and q. Most existing results assume either that a is square-free or that \(\gcd (a, n) = 1\). In this article, we address the case \(n = p^2\) for an odd prime p, without imposing any condition on a. Using the theory of Newton polygons of first and second order, we determine the exact power of each prime q dividing the index \([{\textbf {Z}}_K : {\textbf {Z}}[\theta ]]\). This allows us to construct explicitly a q-integral basis of K for each prime q, which in turn yields a complete integral basis of K. Several illustrative examples are provided. As an application, we show that if a is square-free and satisfies \(a^{p-1} \not \equiv 1 \pmod {p^2}\), then K admits a power basis; that is, \({\textbf {Z}}_K = {\textbf {Z}}[\theta ]\).
期刊介绍:
Acta Mathematica Hungarica is devoted to publishing research articles of top quality in all areas of pure and applied mathematics as well as in theoretical computer science. The journal is published yearly in three volumes (two issues per volume, in total 6 issues) in both print and electronic formats. Acta Mathematica Hungarica (formerly Acta Mathematica Academiae Scientiarum Hungaricae) was founded in 1950 by the Hungarian Academy of Sciences.