A property equivalent to being semi-Kelley

IF 0.6 4区 数学 Q3 MATHEMATICS
Mauricio Chacón-Tirado, María de J. López, Ivon Vidal-Escobar
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引用次数: 0

Abstract

We present a property equivalent to the property of being semi-Kelley. Using this equivalence we prove that being semi-Kelley is a hereditary property for atriodic continua. We prove that semi-Kelley remainders are atriodic, moreover, we prove that semi-Kelley continua are semi-Kelley remainders for chainable continua, circularly chainable continua, and arc continua, and we give an example of an atriodic Kelley continuum which is a semi-Kelley remainder and not a Kelley remainder. We also prove that hereditarily semi-Kelley dendroids are smooth.

相当于半凯利的特性
我们提出了一个与半凯利属性等价的属性。利用这一等价性,我们证明半凯利是无偶性连续性的遗传性质。我们证明了半凯利余数是无征性的,此外,我们还证明了半凯利连续性是可链连续性、圆可链连续性和弧连续性的半凯利余数,并举例说明了无征性凯利连续性是半凯利余数而不是凯利余数。我们还证明了遗传半凯利树枝状体是光滑的。
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来源期刊
CiteScore
1.20
自引率
33.30%
发文量
251
审稿时长
6 months
期刊介绍: Topology and its Applications is primarily concerned with publishing original research papers of moderate length. However, a limited number of carefully selected survey or expository papers are also included. The mathematical focus of the journal is that suggested by the title: Research in Topology. It is felt that it is inadvisable to attempt a definitive description of topology as understood for this journal. Certainly the subject includes the algebraic, general, geometric, and set-theoretic facets of topology as well as areas of interactions between topology and other mathematical disciplines, e.g. topological algebra, topological dynamics, functional analysis, category theory. Since the roles of various aspects of topology continue to change, the non-specific delineation of topics serves to reflect the current state of research in topology. At regular intervals, the journal publishes a section entitled Open Problems in Topology, edited by J. van Mill and G.M. Reed. This is a status report on the 1100 problems listed in the book of the same name published by North-Holland in 1990, edited by van Mill and Reed.
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