On commuting automorphisms of some groups

IF 1.1 4区 数学 Q1 MATHEMATICS
Nazila Azimi Shahrabi, Mehri Akhavan Malayeri
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引用次数: 0

Abstract

Let G be a group. If the set \({\mathcal {A}}(G)=\lbrace \alpha \in {\textit{Aut}}(G): x\alpha (x)=\alpha (x)x\; \textit{for all}\; x\in G\rbrace \) forms a subgroup of \({\textit{Aut}}(G)\), then G is called \({\mathcal {A}}\)-group. In this paper, we prove that a metacyclic group is an \({\mathcal {A}}\)-group. Also, we show that, for any positive integer n and any prime number p, there exists a finite \({\mathcal {A}}\) p-group of nilpotency class n. Since there exist finite non \({\mathcal {A}}\) p-groups with \(\vert G/G^{\prime }\vert = p^{4}\), we find suitable conditions implying that a finite p-group with \(\vert G/G^{\prime }\vert \le p^{3}\) is an \({\mathcal {A}}\)-group. Using these results, we show that there exists a finite \({\mathcal {A}}\) p-group G of order \(p^{n}\) for all \(n\ge 4\) such that \({\mathcal {A}}(G)\) is equal to the central automorphisms group of G. Finally, we use semidirect product and wreath product of groups to obtain suitable examples.

论某些群的换向自形
设 G 是一个群。如果集合 \({\mathcal {A}}(G)=\lbrace \alpha \in {\textit{Aut}}(G): x\alpha (x)=\alpha (x)x\; \textit{for all}\; x\in G\rbrace \) 构成了 \({\textit{Aut}}(G)\) 的一个子群,那么 G 就叫做 \({\mathcal {A}}\)- 群。本文将证明元循环群是一个 ({\mathcal {A}})群。同时,我们还证明了,对于任意正整数 n 和任意素数 p,都存在一个无幂级数 n 的有限的 \({\mathcal {A}}\) p 群。由于存在有限的非\({\mathcal {A}}\) p群,其\(\vert G/G^{\prime }\vert = p^{4}\),我们找到了合适的条件,意味着有限的p群,其\(\vert G/G^{\prime }\vert \le p^{3}\)是一个\({\mathcal {A}}\)群。利用这些结果,我们证明了对于所有的 \(n\ge 4\) 都存在一个阶为 \(p^{n}\) 的有限的 \({\mathcal {A}}(G)\) p 群 G,使得 \({\mathcal {A}}(G)\) 等于 G 的中心自变群。最后,我们利用群的半间接积和花环积来得到合适的例子。
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来源期刊
Ricerche di Matematica
Ricerche di Matematica Mathematics-Applied Mathematics
CiteScore
3.00
自引率
8.30%
发文量
61
期刊介绍: “Ricerche di Matematica” publishes high-quality research articles in any field of pure and applied mathematics. Articles must be original and written in English. Details about article submission can be found online.
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