On a Single Server Vacation Queue with Two Types of Service and Two Types of Vacation

K. C. Madan
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引用次数: 0

Abstract

We study a single server queueing system that receives singly arriving customers according to a Poisson process. The server offers one of the two types of heterogeneous services. Before the beginning of a service, , the customer can choose an exponential service with probability p1 or a deterministic service with probability p2, where p1+p2=1 Immediately after a service is completed, the server has a choice of taking a vacation with probability δ, or, with probability 1-δ, the server may continue staying in the system. We further assume that if the server opts to take a vacation, then with probability α1, he may take a vacation of an exponential duration with mean vacation time 1/u (u>0) or with probability he may want to take a deterministic vacation with constant duration d>0, where α1+α2=1. After a vacation is complete, the server instantly starts providing service if there is at least one customer in the system or the server remains idle in the system till a new customer arrives for service. We find a steady state solution in terms of the generating function of the queue length as well as the steady state probabilities for all different states of the system.
在一台服务器上有两种服务和两种假期的假期队列
我们研究了一个单服务器排队系统,该系统根据泊松过程接收单个到达的客户。服务器提供两种异构服务中的一种。在服务开始前,顾客可以选择概率为 p1 的指数服务或概率为 p2 的确定服务,其中 p1+p2=1 服务完成后,服务器可以立即选择概率为 δ 的休假,或者概率为 1-δ 的继续留在系统中。我们进一步假设,如果服务器选择休假,那么在概率为 α1 的情况下,他可以选择平均休假时间为 1/u (u>0)的指数式休假,或者在概率为 α1+α2=1 的情况下,他可以选择持续时间为 d>0 的确定式休假。休假结束后,如果系统中至少有一个客户,服务器就会立即开始提供服务,否则服务器就会一直处于空闲状态,直到有新的客户到来寻求服务。我们根据队列长度的生成函数以及系统所有不同状态的稳态概率找到了稳态解。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
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CiteScore
0.80
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0.00%
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