A proof of Frankl–Kupavskii's conjecture on edge-union condition

Pub Date : 2024-01-07 DOI:10.1002/jgt.23073
Hongliang Lu, Xuechun Zhang
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引用次数: 0

Abstract

A 3-graph F ${\rm{ {\mathcal F} }}$ is U ( s , 2 s + 1 ) $U(s,2s+1)$ if for any s $s$ edges e 1 , , e s E ( F ) ${e}_{1},\ldots ,{e}_{s}\in E({\rm{ {\mathcal F} }})$ , e 1 e s 2 s + 1 $| {e}_{1}\cup \cdots \cup {e}_{s}| \le 2s+1$ . Frankl and Kupavskii proposed the following conjecture: For any 3-graph F ${\rm{ {\mathcal F} }}$ with n $n$ vertices, if F ${\rm{ {\mathcal F} }}$ is U ( s , 2 s + 1 ) $U(s,2s+1)$ , then

In this paper, we confirm Frankl and Kupavskii's conjecture.

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弗兰克尔-库帕夫斯基关于边缘联合条件猜想的证明
一个 3 图 F${{rm{ {\mathcal F}U(s,2s+1)$U(s,2s+1)$ If for any s$s$ edges e1,...,es∈E(F)${e}_{1},\ldots ,{e}_{s}\in E({\rm{ {mathcal F} }})$, ∣e1∪⋯∪es∣≤2s+1$| {e}_{1}\cup \cdots \cup {e}_{s}| \le 2s+1$.弗兰克尔和库帕夫斯基提出了以下猜想:对于任意 3 图 F${\rm{ {\mathcal F}}$ 有 n$n$ 个顶点,如果 F${\rm{ {\mathcal F}}}$ 是 U(s,2s+1)$U(s,2s+1)$, 那么
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