Calculus

Michael Z. Spivey
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Abstract

The values xi are thus all equal at an extrema. The constraint equation tells us that xi = 1/n, from which we deduce the desired result. This extrema corresponds to a maximum because the continuous function h must achieve both its maximum and minimum value on the compact set [0, 1] and we have already eliminated the minimum by introducing the restriction that the xi are nonzero. (b) Use part (a) to prove, for any n positive numbers ai, i = 1, . . . , n, that
微积分
因此,值xi在极值处都相等。约束方程告诉我们xi = 1/n,由此我们推导出期望的结果。这个极值对应于一个最大值,因为连续函数h必须在紧集[0,1]上同时达到最大值和最小值,而我们已经通过引入xi非零的限制消除了最小值。(b)利用(a)部分证明,对于任意n个正数ai, i = 1,…, n,那
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