胶束萃取富集法测定百里香酚的含量

Elmira I. Tsygulyova, S. Doronin
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引用次数: 0

摘要

为了高效富集4-硝基苯基重氮鎓与百里酚相互作用的偶氮化合物,提出了4-硝基苯胺(4-NA) - NO2- Triton X-100 - NaOH -乙醇体系。确定了该体系胶束饱和相形成的最佳条件:3.10-4 M 4-NA - 3.10-4 M NO2- 5% Triton X-100 - 2.8 M NaOH -10 vol. % С 2Н5ОН。对该体系进行了分光光度法研究。在坐标A (λ max = 552 nm)与r(百里香酚)之间建立了线性关系,其表达式为A = f(c), A = 26291c + 0.02;R2 = 0.997。百里香酚的测定范围为(2·10-6 ~ 4·10-5)mol/l。建立了水介质中百里香酚的比色测定方法(色道G)。通道G色度(IG)的强度与pc(百里香酚)呈线性关系:IG = 54.2pc - 267, r2 = 0;百里香酚的测定下限为1.10 ~ 6 mol/l,比分光光度法测定的下限低2倍。构造了RGB CMYK模型颜色坐标下的花瓣图轮廓;得到了它们的面积(S)和周长(P)与百里香酚浓度的关系(P: y = 278x - 10.13;r2 = 0.97;S: y = 20182x - 87649, r2 = 0.99)。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
Determination of thymol with micellar extraction preconcentration
For the efficient preconcentration of azo compounds – products of the interaction of 4-nitrophenyldiazonium with thymol, a system 4-nitroaniline (4-NA) – NO2- – Triton X-100 – NaOH – ethanol has been proposed. The optimal conditions for the formation of micellarsaturated phases of the system under study have been established: 3.10-4 M 4-NA – 3.10-4 M NO2- – 5% Triton X-100 – 2.8 M NaOH – 10 vol. % С 2Н5ОН. A spectrophotometric study of the above system has been carried out. A linear dependence was built in the coordinates A (at λ max = 552 nm) vs с(thymol), which is described by an equation of the form A = f(c), A = 26291c + 0.02; R2 = 0.997. The range of the determined contents of thymol is (2·10-6 – 4·10-5) mol/l. A technique for the colorimetric determination of thymol in aqueous media (color channel G) has been developed. The intensity of the channel G chromaticity (IG) is linearly dependent on pc(thymol) in accordance with the equation IG = 54.2pc – 267, R 2 = 0; the lower limit of the determined contents of thymol is 1.10-6 mol/l, which is two times less than in the variant of its spectrophotometric determination. The profiles of petal diagrams in the color coordinates of the RGB CMYK model have been constructed; the dependences of their area (S) and perimeter (P) on the thymol concentration have been obtained (P: y = 278x – 10.13; R 2 = 0.97; S: y = 20182x – 87649, R 2 = 0.99).
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