反驳任何CSP的平方和下界

Pravesh Kothari, R. Mori, R. O'Donnell, David Witmer
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引用次数: 91

摘要

设P:{0,1}k→{0,1}是一个非平凡k元谓词。考虑一个约束满足问题(P)的随机实例,在n个变量上有Δ n个约束,每个约束P应用于k个随机选择的字面值。如果约束密度满足Δ > 1,则该实例大概率不满足。反驳问题是如何有效地找到不满足性的证明。我们证明,只要谓词P在其满足的赋值上支持t向均匀概率分布,那么d度的平方和(SOS)算法(运行时间nO(d)) = Θ(n/Δ2/(t-1) logΔ)就不能反驳(P)的随机实例。特别是,多项式时间SOS算法需要Ω(n(t+1)/2)约束来反驳CSP(P)的随机实例,当P在其满足的赋值上支持t向均匀分布时。结合Lee, Raghavendra, Steurer(2015)最近的工作,我们的结果还表明,任何多项式大小的半确定规划松弛用于反驳至少需要Ω(n(t+1)/2)约束。更一般地,我们考虑δ-反驳问题,其目标是证明最多(1 - δ)分数的约束可以同时满足。我们证明,如果P是δ-接近于支持t向均匀分布的满足赋值,那么度-Θ(n/Δ2/(t - 1) logΔ) SOS算法不能(δ+o(1))-驳斥CSP(P)的随机实例。这是第一个表明SOS解决反驳问题所需的程度与解决更难的δ-反驳问题所需的程度之间存在区别的结果。我们的结果(也扩展没有变化的csp在更大的字母)包含所有以前已知的下界的半代数反驳随机csp。对于每个约束谓词P,他们给出了约束密度、SOS度(因此运行时间)和反驳强度之间的三向硬度权衡。根据Allen, O'Donnell, Witmer(2015)和Raghavendra, Rao, Schramm(2016)最近的算法结果,这种完整的三方权衡是紧密的,直到低阶因素。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
Sum of squares lower bounds for refuting any CSP
Let P:{0,1}k → {0,1} be a nontrivial k-ary predicate. Consider a random instance of the constraint satisfaction problem (P) on n variables with Δ n constraints, each being P applied to k randomly chosen literals. Provided the constraint density satisfies Δ ≫ 1, such an instance is unsatisfiable with high probability. The refutation problem is to efficiently find a proof of unsatisfiability. We show that whenever the predicate P supports a t-wise uniform probability distribution on its satisfying assignments, the sum of squares (SOS) algorithm of degree d = Θ(n/Δ2/(t-1) logΔ) (which runs in time nO(d)) cannot refute a random instance of (P). In particular, the polynomial-time SOS algorithm requires Ω(n(t+1)/2) constraints to refute random instances of CSP(P) when P supports a t-wise uniform distribution on its satisfying assignments. Together with recent work of Lee, Raghavendra, Steurer (2015), our result also implies that any polynomial-size semidefinite programming relaxation for refutation requires at least Ω(n(t+1)/2) constraints. More generally, we consider the δ-refutation problem, in which the goal is to certify that at most a (1 - δ)-fraction of constraints can be simultaneously satisfied. We show that if P is δ-close to supporting a t-wise uniform distribution on satisfying assignments, then the degree-Θ(n/Δ2/(t - 1) logΔ) SOS algorithm cannot (δ+o(1))-refute a random instance of CSP(P). This is the first result to show a distinction between the degree SOS needs to solve the refutation problem and the degree it needs to solve the harder δ-refutation problem. Our results (which also extend with no change to CSPs over larger alphabets) subsume all previously known lower bounds for semialgebraic refutation of random CSPs. For every constraint predicate P, they give a three-way hardness tradeoff between the density of constraints, the SOS degree (hence running time), and the strength of the refutation. By recent algorithmic results of Allen, O'Donnell, Witmer (2015) and Raghavendra, Rao, Schramm (2016), this full three-way tradeoff is tight, up to lower-order factors.
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