医疗直线室风管流计算方法的研究

T. Noto, K. Kosako, Takashi Nakamura
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引用次数: 0

摘要

必须抑制医疗直线加速器系统的泄漏辐射剂量,以防止公众暴露于辐射。因此,需要评估通过安装在屏蔽墙上的管道或套管的泄漏剂量,因为辐射可以通过这些管道而不发生散射或衰减。然而,传统的辐射流计算方法尚未充分评估迷宫管道泄漏剂量。本研究对日本放射学会提供的中子和x射线方法、Nakamura和Uwamino的中子公式、IAEA安全报告系列No.47描述的方法和McGinley给出的x射线方法进行了评价,并将结果与计算模型中使用MCNP5的蒙特卡罗计算结果进行了比较。这些模型中的矩形管道位于直线室入口附近的迷宫中。与MCNP5相比,使用传统方法获得的大多数中子管道流结果在2倍之内,而使用x射线的方法获得的结果超过2倍。使用Nakamura和Uwamino的公式计算迷宫流的结果非常一致,差异不超过16%。利用MCNP5的结果,计算了管道入口与出口的x射线剂量之比,研究了x射线管道的流动情况,并显示了与管道开口面积与平方长度之比的关系。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
A study on calculation method of duct streaming from medical linac rooms
The leakage radiation dose from medical linac systems must be suppressed to prevent public exposure to radiation. Therefore, leakage dose through ducts or sleeves installed in shielding walls need to be evaluated because radiation can pass through these without undergoing scattering or attenuation. However, conventional methods for calculating radiation streaming have not been sufficiently evaluated for the leakage dose from the ducts in mazes. In this study, the method provided by the Japan Radiological Society for neutrons and X-rays, Nakamura and Uwamino’s formula for neutrons, the method described by the IAEA Safety Reports Series No.47 and the method given by McGinley for X-rays were evaluated by comparing the results with a Monte Carlo calculation using MCNP5 in calculation models. The rectangular ducts in these models were located in the maze near the entrance of linac room. Compared with MCNP5, most results for duct streaming obtained using conventional methods for neutrons were within a factor of 2, whereas the results of methods using X-rays were more than a factor of 2. The results for maze streaming using Nakamura and Uwamino’s formula were in good agreement and differed by not more than 16%. Furthermore, the ratios of the X-ray dose at the duct entrance to that at the exit were calculated to investigate X-ray duct streaming with the results of MCNP5 and showed the relationships against the ratio of the opening area of the duct to square length.
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