VPI-8的合成。2结晶机理

M Yoshikawa , S.I Zones , M.E Davis
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引用次数: 6

摘要

建立了典型组分Si:Zn=10和Li:Zn=2的硅酸锌锂反应混合物中VPI-8结晶机理的模型。当反应混合物加热到135℃以上的温度时,形成含有均匀分布的硅和锌的非晶凝胶;Si:锌= 8。随着加热时间的推移,锌迁移到凝胶颗粒的表面区域,形成一个缺锌的核心区域,在那里VPI-8发生成核。在核心区VPI-8成核的同时,表面区形成了另外两个富锌相。随着加热时间的延长,富锌相中的一相被溶解,另一相保留,而Si:Zn为27左右的VPI-8的产率增加。最终得到含有少量Si:Zn=1污染相的VPI-8。所建立的VPI-8结晶机理模型与所有已报道的合成和理化数据一致。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
Synthesis of VPI-8. II. Mechanism of crystallization

A model for the crystallization mechanism of VPI-8 from lithium zincosilicate reaction mixtures of typical composition Si:Zn=10 and Li:Zn=2 is presented. When the reaction mixture is heated to temperatures above 135°C, an amorphous gel is formed which contains a homogeneous distribution of silicon and zinc; Si:Zn=8. With heating time, zinc migrates to the superficial region of the gel particles creating a zinc-depleted core region where the nucleation of VPI-8 occurs. Simultaneous with the nucleation of VPI-8 in the core region, two other zinc-rich phases form in the superficial region. As the heating time is increased, one of the zinc-rich phases is dissolved and the other remains while the yield of VPI-8 with a framework Si:Zn of around 27 increases. Ultimately, VPI-8 with a small amount of a contaminating phase with Si:Zn=1 is obtained. The model presented for the crystallization mechanism of VPI-8 is consistent with all reported synthesis and physicochemical data.

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