通过从属关系形成的星形半径

A. Sebastian, V. Ravichandran
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引用次数: 0

摘要

如果关联函数$zf'(z)/f(z)$(或$1+zf''(z)/f'(z)$)是实部正的函数,则开单位盘上的归一化函数$f$是星形(或凸)一元函数。星形半径或凸性半径通常是用实部为正的函数的估计得到的。对于函数$f$,当其$f$为凸形或$(zf'(z)+\alpha z^2f''(z))/f(z)$位于右半平面时,我们利用从属关系研究了各种星形的半径,特别是Janowski星形半径和阶为$\beta$的星形半径。还考虑了与伯努利矩阵和指数函数相关的星似半径。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
Radius of starlikeness through subordination
"A normalized function $f$ on the open unit disc is starlike (or convex) univalent if the associated function $zf'(z)/f(z)$ (or $1+zf''(z)/f'(z)$) is a function with positive real part. The radius of starlikeness or convexity is usually obtained by using the estimates for functions with positive real part. Using subordination, we examine the radius of various starlikeness, in particular, radii of Janowski starlikeness and starlikeness of order $\beta$, for the function $f$ when the function $f$ is either convex or $(zf'(z)+\alpha z^2f''(z))/f(z)$ lies in the right-half plane. Radii of starlikeness associated with lemniscate of Bernoulli and exponential functions are also considered."
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