揭示并解决了麦克斯韦经典电磁场理论中感应电场具有能量的悖论

Shuang-Ren Zhao
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引用次数: 4

摘要

学过电磁场理论的人都知道,磁场的能量密度与磁场强度的平方成正比。电场的能量密度与电场强度的平方成正比。假设电感等器件的尺寸与交流波长相比可以忽略不计,因此电磁辐射可以忽略不计。按照上述方法计算磁场能量是没有问题的。然而,电场有两部分,一部分是静电场,另一部分是感应电场,它与磁矢量势的时间导数有关。很明显,静电场有能量。然而,感应电场是否具有电能尚不清楚。根据麦克斯韦方程,它指的是包含位移电流的辐射电磁场方程,电场的能量自然包括感应电场的能量。而感应电场是一种电磁感应现象,在此过程中磁场的能量有所增加。似乎不应该再计算感应电场本身的能量。另一方面,根据电、磁准静态电磁场方程,感应电磁场没有能量。笔者认为,电、磁类静态电磁场方程是正确的,感应磁场不应具有电场能量。作者认为,这种矛盾是由于麦克斯韦方程(包括位移电流项)不适用于电场和磁场的准静态情况。课本上告诉我们,麦克斯韦方程组是精确方程,磁性准静态或电磁性准静态电磁场方程是麦克斯韦方程组的近似方程。作者认为加入位移电流项得到的麦克斯韦方程可以推导出电磁波的结果,但它仍然是一个问题方程。主要问题是麦克斯韦方程得到的电场和磁场不是电磁场在原电、磁准静态条件下的无缝延伸。也就是说,根据麦克斯韦方程得到的电场和磁场,实际上并不具有原来的电场和磁场的性质。特别是由这种电场和磁场形成的电场能量、磁场能量和坡印亭矢量是不可靠的。在电、磁准静态条件下,最不可靠的是感应电场的能量。感应电场不应有能量。如果感应电场有能量,我们知道能量是二次函数,那么感应电场的能量和静电电场的能量就会有交叉混合的部分,这就更奇怪了。作者认为,在电场和磁场的准静态条件下,Poynting定理仍然是正确的,但由Maxwell方程(包括位移电流)推导出的Poynting定理是不可靠的。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
The Paradox that Induced Electric Field has Energy in Maxwell’s Theory of Classical Electromagnetic Field is Shown and Solved
Those who have studied electromagnetic field theory know that the energy density of the magnetic field is proportional to the square of the magnetic field strength. The energy density of the electric field is proportional to the square of intensity of the electric field. It is assumed that the dimensions of devices such as the inductor are negligible compared with the wavelength of AC, so electromagnetic radiation can be ignore. It is no problem to calculate the energy of the magnetic field according to the above method. However, the electric field has two parts, one is the electrostatic field, and the other is the induced electric field, which is related to the time derivative of the magnetic vector potential. It is also clear that the electrostatic field has energy. However, it is not clear whether the induced electric field has electric energy. According to Maxwell’s equation, it refers to the radiation electromagnetic field equation including displacement current, the energy of the electric field naturally includes the energy of the induced electric field. However, the induced electric field is an electromagnetic induction phenomenon, and the energy of the magnetic field has been increased in this process. It seems that the energy of the induced electric field itself should not be calculated again. On the other hand, according to the electric and magnetic quasi-static electromagnetic field equation, the induced electromagnetic field has no energy. The author believes that the electric and magnetic quasi-static electromagnetic field equation is correct, and the induced magnetic field should not have electric field energy. The author believes that this contradiction is due to the fact that Maxwell’s equation (including displacement current term) is not suitable for the case of electric and magnetic quasi-static fields. As the textbook tells us, Maxwell’s equations are accurate equations, and magnetic quasi-static or electric and magnetic quasi-static electromagnetic field equations are approximate equations of Maxwell’s equations. The author thinks that the Maxwell equation obtained by adding the displacement current term can deduce the result of electromagnetic wave, but it is still a problem equation. The main problem is that the electric field and magnetic field obtained by Maxwell equation are not the seamless extension of the electromagnetic field under the original electric and magnetic quasi-static condition. That is to say, the electric field and magnetic field obtained according to Maxwell’s equation actually do not have the properties of the original electric field and magnetic field. In particular, the electric field energy, magnetic field energy and Poynting vector formed by such electric and magnetic fields are unreliable. In the electric and magnetic quasi-static condition, the most unreliable is the energy of the induced electric field. The induced electric field should not have energy. If the induced electric field has energy, we know that the energy is a quadratic function, so the energy of the induced electric field and the electrostatic electric field will have a cross mixing part, which is even more strange. The author thinks that the Poynting theorem is still correct under the quasi-static condition of electric and magnetic field, but the Poynting theorem derived from Maxwell equation (including displacement current) is not reliable.
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