概率生成函数的对数凹性阈值及相关矩不等式

J. Keilson
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引用次数: 10

摘要

设$\{p_n\}_0^N$是$0 \leqq n \leqq N$上的离散分布,$g(u) = \sum^\infty_0 p_n u^n$是它的$\operatorname{pgf}$。然后对于$0 \leqq t < \infty g_t(u) = g(u + t)/g(1 + t) = \sum^N_0 p_n(t)u^n$是一个由$t$索引的$\operatorname{pgf}$的家族。结果表明,存在一个唯一值$t^\ast$,使得$\{p_n(t)\}_0^N$对于所有$t \geqq t^\ast$都是$\log$ -凹$(PF_2)$,而对于$0 < t < t^\ast$则不是$\log$ -凹。作为结果,人们发现了无限的力矩不等式集$\{\mu_{\lbrack r\rbrack}/\mathbf{r}!\}^{1/r} \geqq \{\mu_{\lbrack r+1\rbrack}/(r + 1)!\}^{1/r+1} \mathbf{r} = 1,2,3,\cdots$等,其中$\mu_{\lbrack r\rbrack}$是$\{p_n\}_0^N$的$\mathbf{r}$次阶乘力矩,当晶格分布为$\log$ -凹时。连续模拟的已知不等式集是由离散不等式推导出来的。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
A Threshold for Log-Concavity for Probability Generating Functions and Associated Moment Inequalities
Let $\{p_n\}_0^N$ be a discrete distribution on $0 \leqq n \leqq N$ and let $g(u) = \sum^\infty_0 p_n u^n$ be its $\operatorname{pgf}$. Then for $0 \leqq t < \infty g_t(u) = g(u + t)/g(1 + t) = \sum^N_0 p_n(t)u^n$ is a family of $\operatorname{pgf}$'s indexed by $t$. It is shown that there is a unique value $t^\ast$ such that $\{p_n(t)\}_0^N$ is $\log$-concave $(PF_2)$ for all $t \geqq t^\ast$ and is not $\log$-concave for $0 < t < t^\ast$. As a consequence one finds the infinite set of moment inequalities $\{\mu_{\lbrack r\rbrack}/\mathbf{r}!\}^{1/r} \geqq \{\mu_{\lbrack r+1\rbrack}/(r + 1)!\}^{1/r+1} \mathbf{r} = 1,2,3,\cdots$ etc. where $\mu_{\lbrack r\rbrack}$ is the $\mathbf{r}$th factorial moment of $\{p_n\}_0^N$ when the lattice distribution is $\log$-concave. The known set of inequalities for the continuous analogue is shown to follow from the discrete inequalities.
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