得到了239Pu在0.005 ~ 0.1 eV范围内的精确裂变截面及其2200 m/s时的参考值

A.J. Deruytter , W. Becker
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引用次数: 8

摘要

在比利时br2反应堆(能量范围为0·000 ~ 0·1 eV)上,用慢波斩波器对239Pu的裂变截面进行了精确测量。同时记录了连续比较的239Pu层和标准元素硼层的脉冲高度和飞行时间谱。利用AuSi表面势垒探测器,在低几何形状条件下对10B(n, α)7Li和239Pu(n, f)反应碎片进行了极好的脉冲高度分辨率检测。239Pu α-粒子产生的堆积尾与裂变碎片能量分布的分离效果很好。通过真空称量,结合对见证箔进行细致的化学和同位素分析,确定了元素硼层中10B的含量。在实验的几何图形中,通过中子计数来检查10B的相对量。利用精确的低几何α-计数和对同位素组成和α-半衰期值的了解,确定了裂变箔上239Pu的含量。测定前后对α-活性进行控制。计算了在0.005 ~ 0.1 eV能量范围内的裂变截面,在2200 m/s时得到的裂变截面绝对值为741·9±3.4 b。这些截面值用于计算20.44°C麦克斯韦中子分布的Westcott g/tf因子,结果为gf = 1.0553±0.013。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
The accurate fission cross-section of 239Pu from 0·005 eV to 0·1 eV and its reference value at 2200 m/s

A precise measurement of the fission cross-section of 239Pu was performed with a slow chopper at the Belgian BR2-reactor (energy range 0·000 to 0·1 eV). Simultaneous recordings of pulse-height and time-of-flight spectra of successively compared 239Pu layers and standard elemental boron layers were made. The detection of the 10B(n, α)7Li and 239Pu(n, ƒ) reaction fragments is made with excellent pulse-height resolution in low geometry with a AuSi surface barrier detector. The separation between the pile-up tail produced by the α-particles of 239Pu and the fission fragment energy-distribution was very good. The amount of 10B in the elemental boron layers was determined by weighing in vacuum combined with careful chemical and isotopic analysis of witness foils. The relative amounts of 10B were checked by neutron-counting in the geometry of the experiment. The amounts of 239Pu on the fission foils were determined from precise low-geometry α-counting and the knowledge of the isotopic composition and α-half-life values. The α-activity was controlled before and after the measurements.

The fission cross-section was calculated in the energy-range from 0·005 to 0·1 eV and its absolute value deduced at 2200 m/s was 741·9 ± 3·4b. These cross-section values were used to calculate the Westcott g/tf-factor for a 20·44°C Maxwellian neutron distribution with as results gƒ = 1·0553 ± 0·0013.

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