不可思议的子序列选择产生正常的数字

J. Vandehey
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引用次数: 5

摘要

给定一个实数0。A1a2a3……这与以b为基数是正常的,我们检查递增的序列ni,使数字0。An1an2an3…都是以b为底的。经典地说,如果ni是等差数列,那么这是可行的。我们给出了几个基于数字ai递归定义的结构,包括ni。特别有趣的是,我们证明了如果一个数是正交于以b为底的,那么从它的展开中去掉所有等于(b - 1)的数字,就会得到一个正交于以(b - 1)为底的以(b - 1)为底的展开。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
Uncanny Subsequence Selections That Generate Normal Numbers
Abstract Given a real number 0.a1a2a3 . . . that is normal to base b, we examine increasing sequences ni so that the number 0.an1an2an3 . . . are normal to base b. Classically, it is known that if the ni form an arithmetic progression, then this will work. We give several more constructions including ni that are recursively defined based on the digits ai. Of particular interest, we show that if a number is normal to base b, then removing all the digits from its expansion which equal (b−1) leaves a base-(b−1) expansion that is normal to base (b − 1)
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