{"title":"斐波那契数是两个平衡数的乘积","authors":"F. Erduvan, R. Keskin","doi":"10.33039/AMI.2019.06.001","DOIUrl":null,"url":null,"abstract":"The Fibonacci sequence (Fn) is defined by F0 = 0, F1 = 1 and Fn = Fn−1 + Fn−2 for n ≥ 2. The balancing number sequence (Bn) is defined by B0 = 0, B1 = 1 and Bn = 6Bn−1 − Bn−2 for n ≥ 2. In this paper, we find all Fibonacci numbers which are products of two balancing numbers. Also we found all balancing numbers which are products of two Fibonacci numbers. More generally, taking k,m,m as positive integers, it is proved that Fk = BmBn implies that (k,m, n) = (1, 1, 1), (2, 1, 1) and Bk = FmFn implies that (k,m, n) = (1, 1, 1), (1, 1, 2), (1, 2, 2), (2, 3, 4).","PeriodicalId":43454,"journal":{"name":"Annales Mathematicae et Informaticae","volume":"252 1","pages":""},"PeriodicalIF":0.3000,"publicationDate":"2019-06-26","publicationTypes":"Journal Article","fieldsOfStudy":null,"isOpenAccess":false,"openAccessPdf":"","citationCount":"2","resultStr":"{\"title\":\"Fibonacci numbers which are products of two balancing numbers\",\"authors\":\"F. Erduvan, R. Keskin\",\"doi\":\"10.33039/AMI.2019.06.001\",\"DOIUrl\":null,\"url\":null,\"abstract\":\"The Fibonacci sequence (Fn) is defined by F0 = 0, F1 = 1 and Fn = Fn−1 + Fn−2 for n ≥ 2. The balancing number sequence (Bn) is defined by B0 = 0, B1 = 1 and Bn = 6Bn−1 − Bn−2 for n ≥ 2. In this paper, we find all Fibonacci numbers which are products of two balancing numbers. Also we found all balancing numbers which are products of two Fibonacci numbers. More generally, taking k,m,m as positive integers, it is proved that Fk = BmBn implies that (k,m, n) = (1, 1, 1), (2, 1, 1) and Bk = FmFn implies that (k,m, n) = (1, 1, 1), (1, 1, 2), (1, 2, 2), (2, 3, 4).\",\"PeriodicalId\":43454,\"journal\":{\"name\":\"Annales Mathematicae et Informaticae\",\"volume\":\"252 1\",\"pages\":\"\"},\"PeriodicalIF\":0.3000,\"publicationDate\":\"2019-06-26\",\"publicationTypes\":\"Journal Article\",\"fieldsOfStudy\":null,\"isOpenAccess\":false,\"openAccessPdf\":\"\",\"citationCount\":\"2\",\"resultStr\":null,\"platform\":\"Semanticscholar\",\"paperid\":null,\"PeriodicalName\":\"Annales Mathematicae et Informaticae\",\"FirstCategoryId\":\"1085\",\"ListUrlMain\":\"https://doi.org/10.33039/AMI.2019.06.001\",\"RegionNum\":0,\"RegionCategory\":null,\"ArticlePicture\":[],\"TitleCN\":null,\"AbstractTextCN\":null,\"PMCID\":null,\"EPubDate\":\"\",\"PubModel\":\"\",\"JCR\":\"Q4\",\"JCRName\":\"MATHEMATICS\",\"Score\":null,\"Total\":0}","platform":"Semanticscholar","paperid":null,"PeriodicalName":"Annales Mathematicae et Informaticae","FirstCategoryId":"1085","ListUrlMain":"https://doi.org/10.33039/AMI.2019.06.001","RegionNum":0,"RegionCategory":null,"ArticlePicture":[],"TitleCN":null,"AbstractTextCN":null,"PMCID":null,"EPubDate":"","PubModel":"","JCR":"Q4","JCRName":"MATHEMATICS","Score":null,"Total":0}
Fibonacci numbers which are products of two balancing numbers
The Fibonacci sequence (Fn) is defined by F0 = 0, F1 = 1 and Fn = Fn−1 + Fn−2 for n ≥ 2. The balancing number sequence (Bn) is defined by B0 = 0, B1 = 1 and Bn = 6Bn−1 − Bn−2 for n ≥ 2. In this paper, we find all Fibonacci numbers which are products of two balancing numbers. Also we found all balancing numbers which are products of two Fibonacci numbers. More generally, taking k,m,m as positive integers, it is proved that Fk = BmBn implies that (k,m, n) = (1, 1, 1), (2, 1, 1) and Bk = FmFn implies that (k,m, n) = (1, 1, 1), (1, 1, 2), (1, 2, 2), (2, 3, 4).