方程x2−(p2q2±3p)y2=±kt的解

Roji Bala, Vinod Mishra
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引用次数: 0

摘要

在本文中,我们求解了方程x2−(p2q2±3p)y2=kt,x2−(p2q2±5p)y2=kt,并用广义Fibonacci,广义Lucas和广义Pell,广义Pell–Lucas序列表示了它的正整数解。借助于该方程,我们已经根据广义Fibonacci、广义Lucas、广义Pell和广义Pell–Lucas数找到了Z[885]和Z[915]的单位。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
Solutions of equations x2−(p2q2±3p)y2=±kt

In the present paper, we have solved the equation x2(p2q2±3p)y2=kt,x2(p2q2±5p)y2=kt and expressed its positive integer solutions in terms of generalized Fibonacci, generalized Lucas and generalized Pell, generalized Pell–Lucas sequences. With the help of this equation, we have found units of Z[885] and Z[915] in terms of generalized Fibonacci, generalized Lucas, generalized Pell and generalized Pell–Lucas numbers.

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