“固有CAT(0)空间的渐近维数和边界维数”的勘误

IF 0.3 Q4 MATHEMATICS
Naotsugu Chinen, T. Hosaka
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引用次数: 0

摘要

. 《数学评论》对[1]的评论指出,其主要结果的证明是不正确的。本文的目的是纠正前一篇论文的论点,澄清陈述。在[2]中指出[1,定理1.1]的证明是不正确的,即映射f不满足ð(cid:1)Þ r,如[1,p. 188]第一段第4行所述。实际上,diam f ð B ð c i k ð x 0 Þ;1 ÞÞ¼diam a 1 ð B ð x 0;1 ÞÞ 0 0每k个A N。在本文中,我们重新定义了¼6 k A N f k: ð Y的映射;R Þ !ð n þ 1;s Þ,特别是f k: c i k ð B ð x 0;K ÞÞ !bn + 1,其中设B ð x0;r Þ¼f y A X: d ð X 0;Y Þ a r g为r > 0。令ð X;d Þ是一个合适的CAT ð 0 Þ空间,设c: ð X;D Þ !ð x;d Þ是一个等距,满足f c i ð x Þ: i A Z g是无界的(见[1,定理1.1])。固定x的点x0。对于每一个ax x,设x x: 1 / 2 0;D ð x0;X Þ(cid:2) !X是从X到X的测地线;D Þ。回想一下投影图p 1: X !B ð x0;1 Þ in [1, p. 187]定义为p 1 ð x Þ¼x x ð min f d ð x 0;X Þ;1 gÞ对应每个x A x。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
Erratum to "Asymptotic dimension and boundary dimension of proper CAT(0) spaces"
. The review on [1] in Mathematical Reviews points out that the proof of its main result is incorrect. The aim of this paper is to correct the previous paper’s argument and clarify the statement. In [2] it is stated that the proof of [1, Theorem 1.1] is incorrect, i.e., the map f does not satisfy ð(cid:1)Þ r , as claimed on line 4 of the first paragraph on [1, p. 188]. In fact, diam f ð B ð c i k ð x 0 Þ ; 1 ÞÞ ¼ diam a 1 ð B ð x 0 ; 1 ÞÞ 0 0 for each k A N . In this paper, we redefine the map f ¼ 6 k A N f k : ð Y ; r Þ ! ð B n þ 1 ; s Þ , in particular f k : c i k ð B ð x 0 ; k ÞÞ ! B n þ 1 , where let B ð x 0 ; r Þ ¼ f y A X : d ð x 0 ; y Þ a r g for r > 0. Let ð X ; d Þ be a proper CAT ð 0 Þ space and let c : ð X ; d Þ ! ð X ; d Þ be an isometry satisfying that f c i ð x Þ : i A Z g is unbounded (see [1, Theorem 1.1]). Fix a point x 0 of X . For every x A X , let x x : ½ 0 ; d ð x 0 ; x Þ(cid:2) ! X be the geodesic from x 0 to x in ð X ; d Þ . Recall the projection map p 1 : X ! B ð x 0 ; 1 Þ in [1, p. 187] defined by p 1 ð x Þ ¼ x x ð min f d ð x 0 ; x Þ ; 1 gÞ for each x A X .
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