带负下标的F(2k)n=+F(2k)m解的上界

Q4 Mathematics
A. Pethö, L. Szalay
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引用次数: 1

摘要

在本文中,我们给出了丢番图方程F(k)n=±F(k)m的解n本文章由计算机程序翻译,如有差异,请以英文原文为准。
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Upper bound on the solution to F(2k)n = +F(2k)m with negative subscripts
In this paper, we provide an explicit upper bound on the absolute value of the solutions n < m < 0 to the Diophantine equation F(k)n = ±F(k)m, assuming k is even. Here {F(k)n}n ∈ Z denotes the k-generalized Fibonacci sequence. The upper bound depends only on k.
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来源期刊
Revista Colombiana de Matematicas
Revista Colombiana de Matematicas Mathematics-Mathematics (all)
CiteScore
0.60
自引率
0.00%
发文量
7
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