{"title":"两组连续平方和的方程","authors":"P. Bush, K. V. Murphy","doi":"10.7546/nntdm.2022.28.4.677-691","DOIUrl":null,"url":null,"abstract":"In this paper we investigate equations featuring sums of consecutive square integers, such as $3^2 + 4^2 = 5^2$, and $108^2 + 109^2 + 110^2 = 133^2 + 134^2$. In general, for a sum of $m+1$ consecutive square integers, $x^2 + (x+1)^2 + \\cdots + (x+m)^2$, there is a distinct set of $m$ consecutive squares, $(x+n)^2 + (x+(n+1))^2 + \\cdots + (x+(n+(m-1)))^2$, to which these are equal. We present a bootstrap method for constructing these equations, which yields solutions comprising an infinite two-dimensional array. We apply a similar method to constructing consecutive square sum equations involving $m+2$ terms on the left, and $m$ terms on the right, formed from two distinct sets of consecutive squares separated one term to the left of the equals sign, such as $2^2 + 3^2 + 6^2 = 7^2$.","PeriodicalId":44060,"journal":{"name":"Notes on Number Theory and Discrete Mathematics","volume":" ","pages":""},"PeriodicalIF":0.4000,"publicationDate":"2022-10-27","publicationTypes":"Journal Article","fieldsOfStudy":null,"isOpenAccess":false,"openAccessPdf":"","citationCount":"0","resultStr":"{\"title\":\"Equations of two sets of consecutive square sums\",\"authors\":\"P. Bush, K. V. Murphy\",\"doi\":\"10.7546/nntdm.2022.28.4.677-691\",\"DOIUrl\":null,\"url\":null,\"abstract\":\"In this paper we investigate equations featuring sums of consecutive square integers, such as $3^2 + 4^2 = 5^2$, and $108^2 + 109^2 + 110^2 = 133^2 + 134^2$. In general, for a sum of $m+1$ consecutive square integers, $x^2 + (x+1)^2 + \\\\cdots + (x+m)^2$, there is a distinct set of $m$ consecutive squares, $(x+n)^2 + (x+(n+1))^2 + \\\\cdots + (x+(n+(m-1)))^2$, to which these are equal. We present a bootstrap method for constructing these equations, which yields solutions comprising an infinite two-dimensional array. We apply a similar method to constructing consecutive square sum equations involving $m+2$ terms on the left, and $m$ terms on the right, formed from two distinct sets of consecutive squares separated one term to the left of the equals sign, such as $2^2 + 3^2 + 6^2 = 7^2$.\",\"PeriodicalId\":44060,\"journal\":{\"name\":\"Notes on Number Theory and Discrete Mathematics\",\"volume\":\" \",\"pages\":\"\"},\"PeriodicalIF\":0.4000,\"publicationDate\":\"2022-10-27\",\"publicationTypes\":\"Journal Article\",\"fieldsOfStudy\":null,\"isOpenAccess\":false,\"openAccessPdf\":\"\",\"citationCount\":\"0\",\"resultStr\":null,\"platform\":\"Semanticscholar\",\"paperid\":null,\"PeriodicalName\":\"Notes on Number Theory and Discrete Mathematics\",\"FirstCategoryId\":\"1085\",\"ListUrlMain\":\"https://doi.org/10.7546/nntdm.2022.28.4.677-691\",\"RegionNum\":0,\"RegionCategory\":null,\"ArticlePicture\":[],\"TitleCN\":null,\"AbstractTextCN\":null,\"PMCID\":null,\"EPubDate\":\"\",\"PubModel\":\"\",\"JCR\":\"Q4\",\"JCRName\":\"MATHEMATICS\",\"Score\":null,\"Total\":0}","platform":"Semanticscholar","paperid":null,"PeriodicalName":"Notes on Number Theory and Discrete Mathematics","FirstCategoryId":"1085","ListUrlMain":"https://doi.org/10.7546/nntdm.2022.28.4.677-691","RegionNum":0,"RegionCategory":null,"ArticlePicture":[],"TitleCN":null,"AbstractTextCN":null,"PMCID":null,"EPubDate":"","PubModel":"","JCR":"Q4","JCRName":"MATHEMATICS","Score":null,"Total":0}
In this paper we investigate equations featuring sums of consecutive square integers, such as $3^2 + 4^2 = 5^2$, and $108^2 + 109^2 + 110^2 = 133^2 + 134^2$. In general, for a sum of $m+1$ consecutive square integers, $x^2 + (x+1)^2 + \cdots + (x+m)^2$, there is a distinct set of $m$ consecutive squares, $(x+n)^2 + (x+(n+1))^2 + \cdots + (x+(n+(m-1)))^2$, to which these are equal. We present a bootstrap method for constructing these equations, which yields solutions comprising an infinite two-dimensional array. We apply a similar method to constructing consecutive square sum equations involving $m+2$ terms on the left, and $m$ terms on the right, formed from two distinct sets of consecutive squares separated one term to the left of the equals sign, such as $2^2 + 3^2 + 6^2 = 7^2$.