{"title":"关于一般域上二重积分和路径积分的一些不等式","authors":"S. Dragomir","doi":"10.30755/nsjom.11914","DOIUrl":null,"url":null,"abstract":"In this paper, by the use of the celebrated Greens identity for double and path integrals, we establish some integral inequalities for functions of two variables de\u0085ned on closed and bounded subsets of the plane R2: Some examples for rectangles and disks are also provided. 1. Introduction In paper [1], the authors obtained among others the following results concerning the di¤erence between the double integral on the disk and the values in the center or the path integral on the circle: Theorem 1. If f : D (C;R) ! R has continuous partial derivatives on D (C;R) ; the disk centered in the point C = (a; b) with the radius R > 0; and @f @x D(C;R);1 : = sup (x;y)2D(C;R) @f (x; y) @x <1; @f @y D(C;R);1 : = sup (x;y)2D(C;R) @f (x; y) @y <1; then (1.1) f (C) 1 R2 ZZ D(C;R) f (x; y) dx dy 4 3 R \" @f @x D(C;R);1 + @f @y D(C;R);1 # : The constant 4 3 is sharp. We also have (1.2) 1 R2 ZZ D(C;R) f (x; y) dx dy 1 2 R Z (C;R) f ( ) dl ( ) 2R 3 \" @f @x D(C;R);1 + @f @y D(C;R);1 # ; 1991 Mathematics Subject Classi\u0085cation. 26D15. Key words and phrases. Double integral, Path integral, Greens identity, Integral inequalities. 1 2 S. S. DRAGOMIR where (C;R) is the circle centered in C = (a; b) with the radius R > 0 and (1.3) f (C) 1 2 R Z (C;R) f ( ) dl ( ) 2R \" @f @x D(C;R);1 + @f @y D(C;R);1 # : In the same paper [1] the authors also established the following Ostrowski type inequality: Theorem 2. If f has bounded partial derivatives on D(0; 1), then (1.4) f (u; v) 1 ZZ D(0;1) f (x; y) dx dy 2 \" @f @x D(0;1);1 u arcsinu+ 1 3 p 1 u2 (2 + u) + @f @y D(0;1);1 v arcsin v + 1 3 p 1 v2 (2 + v) # for any (u; v) 2 D (0; 1). For other integral inequalities for double integrals see [2]-[14]. In this paper, by the use of the celebrated Greens identity for double and path integrals, we establish some integral inequalities for functions of two variables de\u0085ned on closed and bounded subsets of the plane R: Some examples for rectangles and disks are also provided. 2. Main Results Let @D be a simple, closed counterclockwise curve in the xy-plane, bounding a region D. Let L and M be scalar functions de\u0085ned at least on an open set containing D. Assume L and M have continuous \u0085rst partial derivatives. Then the following equality is well known as the Green theorem (see for instance https://en.wikipedia.org/wiki/Green%27s_theorem) (G) Z Z D @M (x; y) @x @L (x; y) @y dxdy = I @D (L (x; y) dx+M (x; y) dy) : Moreover, if the curve @D is described by the function r (t) = (x (t) ; y (t)) ; t 2 [a; b] ; with x, y di¤erentiable on (a; b) then we can calculate the path integral as I @D (L (x; y) dx+M (x; y) dy) = Z b a [L (x (t) ; y (t))x0 (t) +M (x (t) ; y (t)) y0 (t)] dt: By applying this equality for real and imaginary parts, we can also state it for complex valued functions P and Q: INEQUALITIES FOR DOUBLE AND PATH INTEGRALS 3 For a function f : D ! C having partial derivatives on the domain D we de\u0085ne @f;D : D ! C as @f;D (x; y) := (x y) @f (x; y) @x @f (x; y) @y : We need the following identity, [5]: Lemma 1. Let @D be a simple, closed counterclockwise curve in the xy-plane, bounding a region D. Assume that the function f : D ! C has continuous partial derivatives on the domain D: Then 1 2 I @D [(x y) f (x; y) dx+ (x y) f (x; y) dy] Z Z D f (x; y) dxdy (2.1)","PeriodicalId":38723,"journal":{"name":"Novi Sad Journal of Mathematics","volume":" ","pages":""},"PeriodicalIF":0.0000,"publicationDate":"2020-12-28","publicationTypes":"Journal Article","fieldsOfStudy":null,"isOpenAccess":false,"openAccessPdf":"","citationCount":"0","resultStr":"{\"title\":\"On some inequalities for double and path integrals on general domains\\\\footnote{Dedicated to Sienna and Audrey\",\"authors\":\"S. Dragomir\",\"doi\":\"10.30755/nsjom.11914\",\"DOIUrl\":null,\"url\":null,\"abstract\":\"In this paper, by the use of the celebrated Greens identity for double and path integrals, we establish some integral inequalities for functions of two variables de\\u0085ned on closed and bounded subsets of the plane R2: Some examples for rectangles and disks are also provided. 1. Introduction In paper [1], the authors obtained among others the following results concerning the di¤erence between the double integral on the disk and the values in the center or the path integral on the circle: Theorem 1. If f : D (C;R) ! R has continuous partial derivatives on D (C;R) ; the disk centered in the point C = (a; b) with the radius R > 0; and @f @x D(C;R);1 : = sup (x;y)2D(C;R) @f (x; y) @x <1; @f @y D(C;R);1 : = sup (x;y)2D(C;R) @f (x; y) @y <1; then (1.1) f (C) 1 R2 ZZ D(C;R) f (x; y) dx dy 4 3 R \\\" @f @x D(C;R);1 + @f @y D(C;R);1 # : The constant 4 3 is sharp. We also have (1.2) 1 R2 ZZ D(C;R) f (x; y) dx dy 1 2 R Z (C;R) f ( ) dl ( ) 2R 3 \\\" @f @x D(C;R);1 + @f @y D(C;R);1 # ; 1991 Mathematics Subject Classi\\u0085cation. 26D15. Key words and phrases. Double integral, Path integral, Greens identity, Integral inequalities. 1 2 S. S. DRAGOMIR where (C;R) is the circle centered in C = (a; b) with the radius R > 0 and (1.3) f (C) 1 2 R Z (C;R) f ( ) dl ( ) 2R \\\" @f @x D(C;R);1 + @f @y D(C;R);1 # : In the same paper [1] the authors also established the following Ostrowski type inequality: Theorem 2. If f has bounded partial derivatives on D(0; 1), then (1.4) f (u; v) 1 ZZ D(0;1) f (x; y) dx dy 2 \\\" @f @x D(0;1);1 u arcsinu+ 1 3 p 1 u2 (2 + u) + @f @y D(0;1);1 v arcsin v + 1 3 p 1 v2 (2 + v) # for any (u; v) 2 D (0; 1). For other integral inequalities for double integrals see [2]-[14]. In this paper, by the use of the celebrated Greens identity for double and path integrals, we establish some integral inequalities for functions of two variables de\\u0085ned on closed and bounded subsets of the plane R: Some examples for rectangles and disks are also provided. 2. Main Results Let @D be a simple, closed counterclockwise curve in the xy-plane, bounding a region D. Let L and M be scalar functions de\\u0085ned at least on an open set containing D. Assume L and M have continuous \\u0085rst partial derivatives. Then the following equality is well known as the Green theorem (see for instance https://en.wikipedia.org/wiki/Green%27s_theorem) (G) Z Z D @M (x; y) @x @L (x; y) @y dxdy = I @D (L (x; y) dx+M (x; y) dy) : Moreover, if the curve @D is described by the function r (t) = (x (t) ; y (t)) ; t 2 [a; b] ; with x, y di¤erentiable on (a; b) then we can calculate the path integral as I @D (L (x; y) dx+M (x; y) dy) = Z b a [L (x (t) ; y (t))x0 (t) +M (x (t) ; y (t)) y0 (t)] dt: By applying this equality for real and imaginary parts, we can also state it for complex valued functions P and Q: INEQUALITIES FOR DOUBLE AND PATH INTEGRALS 3 For a function f : D ! C having partial derivatives on the domain D we de\\u0085ne @f;D : D ! C as @f;D (x; y) := (x y) @f (x; y) @x @f (x; y) @y : We need the following identity, [5]: Lemma 1. Let @D be a simple, closed counterclockwise curve in the xy-plane, bounding a region D. Assume that the function f : D ! C has continuous partial derivatives on the domain D: Then 1 2 I @D [(x y) f (x; y) dx+ (x y) f (x; y) dy] Z Z D f (x; y) dxdy (2.1)\",\"PeriodicalId\":38723,\"journal\":{\"name\":\"Novi Sad Journal of Mathematics\",\"volume\":\" \",\"pages\":\"\"},\"PeriodicalIF\":0.0000,\"publicationDate\":\"2020-12-28\",\"publicationTypes\":\"Journal Article\",\"fieldsOfStudy\":null,\"isOpenAccess\":false,\"openAccessPdf\":\"\",\"citationCount\":\"0\",\"resultStr\":null,\"platform\":\"Semanticscholar\",\"paperid\":null,\"PeriodicalName\":\"Novi Sad Journal of Mathematics\",\"FirstCategoryId\":\"1085\",\"ListUrlMain\":\"https://doi.org/10.30755/nsjom.11914\",\"RegionNum\":0,\"RegionCategory\":null,\"ArticlePicture\":[],\"TitleCN\":null,\"AbstractTextCN\":null,\"PMCID\":null,\"EPubDate\":\"\",\"PubModel\":\"\",\"JCR\":\"Q3\",\"JCRName\":\"Mathematics\",\"Score\":null,\"Total\":0}","platform":"Semanticscholar","paperid":null,"PeriodicalName":"Novi Sad Journal of Mathematics","FirstCategoryId":"1085","ListUrlMain":"https://doi.org/10.30755/nsjom.11914","RegionNum":0,"RegionCategory":null,"ArticlePicture":[],"TitleCN":null,"AbstractTextCN":null,"PMCID":null,"EPubDate":"","PubModel":"","JCR":"Q3","JCRName":"Mathematics","Score":null,"Total":0}
引用次数: 0
摘要
本文利用二重积分和路径积分的著名格林恒等式,建立了平面R2的闭子集和有界子集上定义的两个变量函数的一些积分不等式:并给出了矩形和圆盘的一些例子。1.引言在文[1]中,作者得到了关于圆盘上的二重积分与中心值或圆上的路径积分之差的以下结果:定理1。如果f:D(C;R)!R在D(C;R)上具有连续偏导数;以点C为中心的圆盘=(a;b),半径R>0;和@f@xD(C;R);1:=sup(x;y)2D(C;R)@f。如果f在D(0;1)上具有有界偏导数,则(1.4)f(u;v)1 ZZ D(0;1)f(x;y)dx dy 2“@f@x D(0,1);1 u arcsinu+13 p1u2(2+u)+@f@y D(0);1 v arcsin v+13 p1v2(2+v本文利用二重积分和路径积分的著名格林恒等式,建立了平面R的闭子集和有界子集上定义的两个变量函数的一些积分不等式:并给出了矩形和圆盘的一些例子。2.主要结果设@D是xy平面上的一条简单的逆时针闭合曲线,边界为区域D。设L和M是至少在包含D的开集上定义的标量函数。假定L和M具有连续的一阶偏导数。那么下面的等式就是众所周知的格林定理(例如https://en.wikipedia.org/wiki/Green%27s_theorem)(G)Z Z D@M(x;y)@x@L(x;y)@y dxdy=I@D(L(x,y)dx+M(x,y)dy):此外,如果曲线@D由函数r(t)=(x(t)描述;y(t));t2[a;b];如果x,y在(a;b)上是可微分的,那么我们可以将路径积分计算为I@D(L(x;y)dx+M(x;y)dy)=Z b a[L(x(t);y(t))x0(t)+M(x(t),y(t!C在域D上具有偏导数,我们定义为@f;D:D!C为@f;D(x;y):=(xy)@f(x;y)@x@f(x;y)@y:我们需要以下恒等式[5]:引理1。设@D是xy平面上的一条简单的逆时针闭合曲线,边界为区域D。假设函数f:D!C在域D上具有连续偏导数:则12 I@D[(xy)f(x;y)dx+(xy)f(x;y)dy]Z Z D f(x,y)dxdy(2.1)
On some inequalities for double and path integrals on general domains\footnote{Dedicated to Sienna and Audrey
In this paper, by the use of the celebrated Greens identity for double and path integrals, we establish some integral inequalities for functions of two variables de ned on closed and bounded subsets of the plane R2: Some examples for rectangles and disks are also provided. 1. Introduction In paper [1], the authors obtained among others the following results concerning the di¤erence between the double integral on the disk and the values in the center or the path integral on the circle: Theorem 1. If f : D (C;R) ! R has continuous partial derivatives on D (C;R) ; the disk centered in the point C = (a; b) with the radius R > 0; and @f @x D(C;R);1 : = sup (x;y)2D(C;R) @f (x; y) @x <1; @f @y D(C;R);1 : = sup (x;y)2D(C;R) @f (x; y) @y <1; then (1.1) f (C) 1 R2 ZZ D(C;R) f (x; y) dx dy 4 3 R " @f @x D(C;R);1 + @f @y D(C;R);1 # : The constant 4 3 is sharp. We also have (1.2) 1 R2 ZZ D(C;R) f (x; y) dx dy 1 2 R Z (C;R) f ( ) dl ( ) 2R 3 " @f @x D(C;R);1 + @f @y D(C;R);1 # ; 1991 Mathematics Subject Classi cation. 26D15. Key words and phrases. Double integral, Path integral, Greens identity, Integral inequalities. 1 2 S. S. DRAGOMIR where (C;R) is the circle centered in C = (a; b) with the radius R > 0 and (1.3) f (C) 1 2 R Z (C;R) f ( ) dl ( ) 2R " @f @x D(C;R);1 + @f @y D(C;R);1 # : In the same paper [1] the authors also established the following Ostrowski type inequality: Theorem 2. If f has bounded partial derivatives on D(0; 1), then (1.4) f (u; v) 1 ZZ D(0;1) f (x; y) dx dy 2 " @f @x D(0;1);1 u arcsinu+ 1 3 p 1 u2 (2 + u) + @f @y D(0;1);1 v arcsin v + 1 3 p 1 v2 (2 + v) # for any (u; v) 2 D (0; 1). For other integral inequalities for double integrals see [2]-[14]. In this paper, by the use of the celebrated Greens identity for double and path integrals, we establish some integral inequalities for functions of two variables de ned on closed and bounded subsets of the plane R: Some examples for rectangles and disks are also provided. 2. Main Results Let @D be a simple, closed counterclockwise curve in the xy-plane, bounding a region D. Let L and M be scalar functions de ned at least on an open set containing D. Assume L and M have continuous rst partial derivatives. Then the following equality is well known as the Green theorem (see for instance https://en.wikipedia.org/wiki/Green%27s_theorem) (G) Z Z D @M (x; y) @x @L (x; y) @y dxdy = I @D (L (x; y) dx+M (x; y) dy) : Moreover, if the curve @D is described by the function r (t) = (x (t) ; y (t)) ; t 2 [a; b] ; with x, y di¤erentiable on (a; b) then we can calculate the path integral as I @D (L (x; y) dx+M (x; y) dy) = Z b a [L (x (t) ; y (t))x0 (t) +M (x (t) ; y (t)) y0 (t)] dt: By applying this equality for real and imaginary parts, we can also state it for complex valued functions P and Q: INEQUALITIES FOR DOUBLE AND PATH INTEGRALS 3 For a function f : D ! C having partial derivatives on the domain D we de ne @f;D : D ! C as @f;D (x; y) := (x y) @f (x; y) @x @f (x; y) @y : We need the following identity, [5]: Lemma 1. Let @D be a simple, closed counterclockwise curve in the xy-plane, bounding a region D. Assume that the function f : D ! C has continuous partial derivatives on the domain D: Then 1 2 I @D [(x y) f (x; y) dx+ (x y) f (x; y) dy] Z Z D f (x; y) dxdy (2.1)