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引用次数: 0
摘要
摘要设$\omega^*(n)$是素数p的个数,使得$p-1$除n。最近,M.R.Murty和V.K.Murty证明了$$\boot{align*}x(\log\logx)^3\lll\sum_{n\le x}\omega^*(n x\rightarrow\infty$。在这个简短的注释中,我们给出了和的正确顺序,通过显示$$\ begin{align*}\sum_{n\le x}\omega^*(n)^2 \symp x \log x \end{align*}$$
Abstract Let
$\omega ^*(n)$
be the number of primes p such that
$p-1$
divides n. Recently, M. R. Murty and V. K. Murty proved that
$$ \begin{align*}x(\log\log x)^3\ll\sum_{n\le x}\omega^*(n)^2\ll x\log x.\end{align*} $$
They further conjectured that there is some positive constant C such that
$$ \begin{align*}\sum_{n\le x}\omega^*(n)^2\sim Cx\log x,\end{align*} $$
as
$x\rightarrow \infty $
. In this short note, we give the correct order of the sum by showing that
$$ \begin{align*}\sum_{n\le x}\omega^*(n)^2\asymp x\log x.\end{align*} $$