量子游戏中获胜的最佳策略

IF 2.2
Michael Schleppy;Emina Soljanin;Nicolas Swanson
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引用次数: 0

摘要

在最近推出的coset猜谜游戏中,爱丽丝与鲍勃和查理对抗,目的是满足共同获胜的条件。鲍勃和查理只有在游戏开始前才能沟通,以设计一个共同的策略。我们考虑的游戏开始于Alice基于随机选择的三个参数准备一个价值200万美元的量子比特量子态。她将前m个量子位发送给Bob,其余的发送给Charlie,然后向他们透露她对其中一个参数的选择。鲍勃应该猜出其中一个隐藏参数,查理猜出另一个,如果两个猜测都正确,他们就赢了。从之前的工作中,我们知道Bob和Charlie同时猜对的概率随着m的增加呈指数增长为零。我们推导出这个概率的严格上界,并展示鲍勃和查理如何实现它。在开发最佳策略时,我们设计了一个仅使用CNOT和Hadamard门的编码电路,该电路仅使用局部操作从EPR对构建CSS代码。我们发现,Alice与Bob和Charlie交流的量子信息的作用是使他们的回答相互关联,而不是提高他们的个人(边际)正确猜测率。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
Optimal Strategies for Winning Certain Coset-Guessing Quantum Games
In a recently introduced coset guessing game, Alice plays against Bob and Charlie, aiming to meet a joint winning condition. Bob and Charlie can only communicate before the game starts to devise a joint strategy. The game we consider begins with Alice preparing a $2m$ -qubit quantum state based on a random selection of three parameters. She sends the first m qubits to Bob and the rest to Charlie, and then reveals to them her choice for one of the parameters. Bob is supposed to guess one of the hidden parameters, Charlie the other, and they win if both guesses are correct. From previous work, we know that the probability of Bob’s and Charlie’s guesses being simultaneously correct goes to zero exponentially as m increases. We derive a tight upper bound on this probability and show how Bob and Charlie can achieve it. While developing an optimal strategy, we devised an encoding circuit using only CNOT and Hadamard gates, which builds CSS codes from EPR pairs using only local operations. We found that the role of quantum information that Alice communicates to Bob and Charlie is to make their responses correlated rather than improve their individual (marginal) correct guessing rates.
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来源期刊
CiteScore
8.20
自引率
0.00%
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