智能交通系统协议互操作性评估

IF 4.6 Q2 COMPUTER SCIENCE, ARTIFICIAL INTELLIGENCE
Jonas Vogt;Hans D. Schotten;Horst Wieker
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引用次数: 0

摘要

几十年来,移动领域的系统一直被维持为独立的实体。他们必须合作,以提高交通安全和效率,同时减少环境污染。在正式分离的生态系统中使用的协议展示了不同的行为和数据表示。为了促进这些生态系统之间的连接,我们建议引入智能交通系统协议互操作性评估(ITS-PIE)。评估方法允许系统架构师和开发人员在六个步骤的过程中分析现有协议。第一步是评估相互依赖性,确定两个协议规范之间的任何正式或非正式的相关性。第二步是对协议的非正式描述和正式描述进行正式分类,强调规范的异同。形式比较计算形式规范之间的共识并行性。数据评估定义了工具,以一种可以执行自动转换的方式来描述规范。协议的体系结构上下文评估显示框架条件。最后一步是根据情况进行解释。这里提供了两个说明性的例子来说明评估的优点,并强调在此过程中出现的主要挑战。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
Intelligent Transportation System Protocol Interoperability Evaluation
For decades, systems in the mobility sector have been maintained as discrete entities. It is imperative that they collaborate in order to enhance traffic safety and efficiency, while simultaneously reducing environmental pollution. The protocols employed in the formally separated ecosystems demonstrate disparate behaviors and data representations. In order to facilitate connectivity between these ecosystems, we propose the introduction of the Intelligent Transportation System Protocol Interoperability Evaluation (ITS-PIE). The evaluation method allows system architects and developers to analyze existing protocols in a six-step process. The initial step is the assessment of interdependencies, which identifies any formal or informal correlation between two protocol specifications. The second step is the formal classification of the protocols’ informal and formal descriptions, which emphasizes the specification’s similarities and differences. The formal comparison calculates the consensual parallelisms between the formal specifications. The data evaluation defines tooling to describe the specifications in a way that an automated transition can be conducted. The protocols’ architecture context evaluation displays the framework conditions. The final step is a situation-dependent interpretation. Two illustrative examples are provided herein to illustrate the advantages of the evaluation and to highlight the principal challenges that arise during the process.
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CiteScore
5.40
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