平超复数无穷折线是(\mathbb H\ )可解的

Pub Date : 2024-10-14 DOI:10.1134/S001626632403002X
Yulia Gorginyan
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引用次数: 0

摘要

让 \(\mathbb H\) 是一个由 \(I,J\) 和 \(K\) 生成的四元数代数。如果存在一个包含 \(\mathfrak g_{i+1}=[\mathfrak g_i,\mathfrak g_i]\)的 \(\mathbb H\)-invariant 子代数序列,那么我们说一个超复数零能烈代数是 \(\mathbb H\)-solvable 的、 使得([\mathfrak g_i^{\mathbb H}、\和(\mathfrak g_{i+1}^{\mathbb H}=\mathbb H[\mathfrak g_i^{\mathbb H},\mathfrak g_i^{\mathbb H}] \)。让(N=\Gamma\setminus G\) 是一个具有平面小畑(Obata)连接的超复数无芒点,并且(\mathfrak g=\operatorname{Lie}(G)\)是一个具有平面小畑(Obata)连接的超复数无芒点。我们证明了烈代数((\mathfrak g\) is \(\mathbb H\) -solvable.
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Flat Hypercomplex Nilmanifolds are \(\mathbb H\)-Solvable

Let \(\mathbb H\) be a quaternion algebra generated by \(I,J\) and \(K\). We say that a hypercomplex nilpotent Lie algebra \(\mathfrak g\) is \(\mathbb H\)-solvable if there exists a sequence of \(\mathbb H\)-invariant subalgebras containing \(\mathfrak g_{i+1}=[\mathfrak g_i,\mathfrak g_i]\),

such that \([\mathfrak g_i^{\mathbb H},\mathfrak g_i^{\mathbb H}]\subset\mathfrak g^{\mathbb H}_{i+1}\) and \(\mathfrak g_{i+1}^{\mathbb H}=\mathbb H[\mathfrak g_i^{\mathbb H},\mathfrak g_i^{\mathbb H}] \). Let \(N=\Gamma\setminus G\) be a hypercomplex nilmanifold with the flat Obata connection and \(\mathfrak g=\operatorname{Lie}(G)\). We prove that the Lie algebra \(\mathfrak g\) is \(\mathbb H\)-solvable.

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