改进的 $D^0 \to K^-\ell^+ν_ell$ 和 $D^+ \to \bar K^0\ell^+ν_ell$ 测量方法

BESIII Collaboration
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引用次数: 0

摘要

利用 BESIII 探测器在质量中心能量 3.773GeV,我们测得$D^0\to K^-e^+\nu_e$、$D^0\to K^-\mu^+\nu_mu$、$D^+\bar K^0e^+\nu_e$和$D^+\bar K^0\mu^+\nu_mu$的绝对分支分数分别为$(3.%$,$(3.408\pm0.011_\{rmstat.}\pm0.013_{rm syst.})(%$),$(8.856\pm0.039_{\rm stat.}\pm0.078_{\rmsyst.}) (%$)和 $(8.661\pm0.046_{\rm stat.}\pm0.080_{\rm syst.}) (%$)。通过同时拟合这四种衰变的部分衰变率,确定了强子形式因子$f^K_+(0)$与$c\to s$ CKM矩阵元素$|V_{cs}|$的乘积为$f^K_+(0)|V_{cs}|=0.7162/pm0.0011_{/rm stat.}/pm0.0012_{/rm syst.}$。以标准模型全局拟合中的 $|V_{cs}|=0.97349\pm0.00016$ 和 LQCD 计算中的 $f^K_+(0)=0.7452\pm0.0031$ 作为输入,我们得到了 $f^K_+(0)=0.97349\pm0.00016$ 和 $f^K_+(0)=0.7452\pm0.0031$ 的结果。7357\pm0.0011_{\rm stat.}\pm0.0012_{\rm syst.}$和 $|V_{cs}|=0.9611\pm0.0015_{\rm stat.}\pm0.0016_{\rm syst.}\pm0.0040_{\rmLQCD}$.
本文章由计算机程序翻译,如有差异,请以英文原文为准。
Improved measurements of $D^0 \to K^-\ell^+ν_\ell$ and $D^+ \to \bar K^0\ell^+ν_\ell$
Using 7.93 fb$^{-1}$ of $e^+e^-$ collision data collected at the center-of-mass energy of 3.773 GeV with the BESIII detector, we measure the absolute branching fractions of $D^0\to K^-e^+\nu_e$, $D^0\to K^-\mu^+\nu_\mu$, $D^+\to \bar K^0e^+\nu_e$, and $D^+\to \bar K^0\mu^+\nu_\mu$ to be $(3.509\pm0.009_{\rm stat.}\pm0.013_{\rm syst.}) \%$, $(3.408\pm0.011_{\rm stat.}\pm0.013_{\rm syst.}) \%$, $(8.856\pm0.039_{\rm stat.}\pm0.078_{\rm syst.}) \%$, and $(8.661\pm0.046_{\rm stat.}\pm0.080_{\rm syst.}) \%$, respectively. By performing a simultaneous fit to the partial decay rates of these four decays, the product of the hadronic form factor $f^K_+(0)$ and the modulus of the $c\to s$ CKM matrix element $|V_{cs}|$ is determined to be $f^K_+(0)|V_{cs}|=0.7162\pm0.0011_{\rm stat.}\pm0.0012_{\rm syst.}$. Taking the value of $|V_{cs}|=0.97349\pm0.00016$ from the standard model global fit or that of $f^K_+(0)=0.7452\pm0.0031$ from the LQCD calculation as input, we derive the results $f^K_+(0)=0.7357\pm0.0011_{\rm stat.}\pm0.0012_{\rm syst.}$ and $|V_{cs}|=0.9611\pm0.0015_{\rm stat.}\pm0.0016_{\rm syst.}\pm0.0040_{\rm LQCD}$.
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