同构自动机网络的交互图 II:通用动力学

Florian Bridoux, Aymeric Picard Marchetto, Adrien Richard
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引用次数: 0

摘要

在大小为$q$的有限字母表$Q$上有$n$组件的自动机网络是一个离散动力系统,由函数$f:Q^n\to Q^n$的连续迭代所描述。在大多数应用中,主要参数是$f$的交互图:如果$f_i$依赖于输入$j$,则包含从$j$到$i$的弧的顶点集$[n]$的数图。关于与$f$同构的自动机网络的交互图集$mathbb{G}(f)$,我们能说些什么呢?这个简单的问题似乎从未有人研究过。在上一篇论文中,我们证明了具有 $n^2$ 个弧的完整数图 $K_n$ 在 $f$ 不是常数也不是同一性(且 $n\geq 5$)时,在 $K_n\in \mathbb{G}(f)$ 中是通用的。实际上,我们证明了$\mathbb{G}(f)$中只存在三个特定的数字图意味着$f$的普遍性,我们还证明了这迫使字母表大小$q$至少有$n$素因子(具有多重性)。然而,我们证明,对于任何固定的 $q\geq 3$,都存在几乎是普遍的函数,即函数 $f:Q^n\to Q^n$,使得随机图属于 $\mathbb{G}(f)$ 的概率随着 $n\to\infty$ 的增大而趋向于 $1$。我们不知道这在二进制情况 $q=2$ 中是否成立,因此只提供了部分结果。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
Interaction graphs of isomorphic automata networks II: universal dynamics
An automata network with $n$ components over a finite alphabet $Q$ of size $q$ is a discrete dynamical system described by the successive iterations of a function $f:Q^n\to Q^n$. In most applications, the main parameter is the interaction graph of $f$: the digraph with vertex set $[n]$ that contains an arc from $j$ to $i$ if $f_i$ depends on input $j$. What can be said on the set $\mathbb{G}(f)$ of the interaction graphs of the automata networks isomorphic to $f$? It seems that this simple question has never been studied. In a previous paper, we prove that the complete digraph $K_n$, with $n^2$ arcs, is universal in that $K_n\in \mathbb{G}(f)$ whenever $f$ is not constant nor the identity (and $n\geq 5$). In this paper, taking the opposite direction, we prove that there exists universal automata networks $f$, in that $\mathbb{G}(f)$ contains all the digraphs on $[n]$, excepted the empty one. Actually, we prove that the presence of only three specific digraphs in $\mathbb{G}(f)$ implies the universality of $f$, and we prove that this forces the alphabet size $q$ to have at least $n$ prime factors (with multiplicity). However, we prove that for any fixed $q\geq 3$, there exists almost universal functions, that is, functions $f:Q^n\to Q^n$ such that the probability that a random digraph belongs to $\mathbb{G}(f)$ tends to $1$ as $n\to\infty$. We do not know if this holds in the binary case $q=2$, providing only partial results.
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