论特征$p>0$中阶$p$的${\bf A}^n$自形变的指数性

Shigeru Kuroda
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引用次数: 0

摘要

让 $X$ 是特征为 $p>0$ 的积分仿射方案,并且 $\sigma $ 是 $X$ 的非同一性自变量。如果 $\sigma $ 是 $textit{exponential}$,即由 ${\bf G}_a$ 作用于 $X$ 所诱导,那么 $\sigma $ 显然是阶为 $p$的。不难看出,一般情况下相反的情况并不成立。事实上,存在着这样的$X$,它允许一个阶为$p$的自变量,却不允许任何非琐${\bf G}_a$作用。然而,在$X$是仿射空间${\bf A}_R^n$的情况下,情况就不清楚了,因为${\bf A}_R^n$允许各种${\bfG}_a$作用以及阶$p$的自变量。在本文中,我们研究了 ${\bf A}_R^n$ 的阶 $p$ 自形变的指数性,其中的困难源于诱导指数自形变的 ${\bfG}_a$ 作用的非唯一性。我们的主要结果如下(1) 我们证明了在某些低维情况下,阶为 $p$ 的 ${\bf A}_R^n$ 的三角自形变是指数级的。(2) 我们为每个 $n\ge 2$ 构造了 ${\bf A}_R^n$ 的非指数阶自形变。这里,$R$ 是任何非场的 UFD。(3) 我们研究了诱导 ${\bf A}_R^n$ 元自形性的 ${\bf G}_a$ 作用。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
On exponentiality of automorphisms of ${\bf A}^n$ of order $p$ in characteristic $p>0$
Let $X$ be an integral affine scheme of characteristic $p>0$, and $\sigma $ a non-identity automorphism of $X$. If $\sigma $ is $\textit{exponential}$, i.e., induced from a ${\bf G}_a$-action on $X$, then $\sigma $ is obviously of order $p$. It is easy to see that the converse is not true in general. In fact, there exists $X$ which admits an automorphism of order $p$, but admits no non-trivial ${\bf G}_a$-actions. However, the situation is not clear in the case where $X$ is the affine space ${\bf A}_R^n$, because ${\bf A}_R^n$ admits various ${\bf G}_a$-actions as well as automorphisms of order $p$. In this paper, we study exponentiality of automorphisms of ${\bf A}_R^n$ of order $p$, where the difficulty stems from the non-uniqueness of ${\bf G}_a$-actions inducing an exponential automorphism. Our main results are as follows. (1) We show that the triangular automorphisms of ${\bf A}_R^n$ of order $p$ are exponential in some low-dimensional cases. (2) We construct a non-exponential automorphism of ${\bf A}_R^n$ of order $p$ for each $n\ge 2$. Here, $R$ is any UFD which is not a field. (3) We investigate the ${\bf G}_a$-actions inducing an elementary automorphism of ${\bf A}_R^n$.
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