斯坦纳树的双向切割松弛具有小于 2 的积分差距

Jarosław Byrka, Fabrizio Grandoni, Vera Traub
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引用次数: 0

摘要

斯坦纳树问题是网络设计中最突出的问题之一。给定一个有边加权的无向图和一个称为终端的顶点子集,任务是计算一棵包含所有终端(可能还有更多顶点)的最小权树。最著名的斯坦纳树近似计算算法需要枚举大量(多项式但)候选成分,因此在实际应用中速度很慢。双向切分松弛(BCR)是设计快速准确的斯坦纳树近似计算法的一个有前途的要素:双向切分所有边,选择一个任意终端作为根,并强制要求每个包含某些终端但不是根的切分都有一个单位的分数边离开它。众所周知,在生成树的情况下 BCR 是积分的[Edmonds'67],即所有顶点都是终端时。我们通过证明 BCR 的积分差距上限 1.9988 来解决这个问题。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
The Bidirected Cut Relaxation for Steiner Tree has Integrality Gap Smaller than 2
The Steiner tree problem is one of the most prominent problems in network design. Given an edge-weighted undirected graph and a subset of the vertices, called terminals, the task is to compute a minimum-weight tree containing all terminals (and possibly further vertices). The best-known approximation algorithms for Steiner tree involve enumeration of a (polynomial but) very large number of candidate components and are therefore slow in practice. A promising ingredient for the design of fast and accurate approximation algorithms for Steiner tree is the bidirected cut relaxation (BCR): bidirect all edges, choose an arbitrary terminal as a root, and enforce that each cut containing some terminal but not the root has one unit of fractional edges leaving it. BCR is known to be integral in the spanning tree case [Edmonds'67], i.e., when all the vertices are terminals. For general instances, however, it was not even known whether the integrality gap of BCR is better than the integrality gap of the natural undirected relaxation, which is exactly 2. We resolve this question by proving an upper bound of 1.9988 on the integrality gap of BCR.
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