对霍普-塞勒黄嘌呤测试机制的深入了解

Francisco Sánchez-Viesca, Reina Gómez
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引用次数: 0

摘要

黄嘌呤作为一种重要的生物大分子,引起了学者们从不同角度的关注。在分析领域,已经开发出了一些用于鉴定的测试方法。霍普-塞勒(Hoppe-Seyler)使用氯次氯酸钙和氢氧化钠检测黄嘌呤,因为形成的绿色环会变成棕色。对于理论化学家来说,要弄清检测过程中分子水平发生了什么变化是一项挑战。在这篇通讯中,重点放在反应序列中出现的反应性三极中间体上。即羧酸盐和新形成的齐聚物。与水反应可以消除最后一个偶极(带负电荷的氮和羰离子)。但是,还有一对离子是相连的:羧酸根离子和位于 β 位的羰离子。这种情况会立即产生脱羧反应,以单一的内部方式消除两个电荷,形成双键。带负电荷的氮原子中和后生成脲基。这一反应顺序产生了主要反应产物咪唑-咪唑啉酮。观察到的颜色是由于卤代色素造成的。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
An insight on the mechanism of the Hoppe-Seyler test for xanthine
Being xanthine an important biomolecule, it has attracted the attention of scholars from different points of view. In the analytical field some tests for identification have been developed. Hoppe-Seyler detected xanthine using calcium chlorohypochlorite and sodium hydroxide since a green ring, changing to brown, is formed. It is a challenge to the theoretical chemist disentangle what is happening at molecular level during the assay. In this communication emphasis is placed in a reactive tri-polar intermediate that arises in a reaction sequence. That is, a carboxylate and a newly formed zwitterion. Reaction with water can eliminate the last dipole (a negatively charged nitrogen and a carbonium ion). However, there is other pair of ions that are connected: the carboxylate and the carbonium ion at β-position. This situation produces immediate decarboxylation, eliminating two electrical charges in a single internal way, and forming a double bond. Neutralization of the negatively charged nitrogen atom gives an ureido. This reaction sequence produces the principal reaction product, imidazo-imidazolone. The observed colours are due to halochromism.
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