利用格拉斯曼图恢复基本投影几何

IF 0.6 4区 数学 Q3 MATHEMATICS
Ian Seong
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引用次数: 0

摘要

让 n、k 表示具有 \(n>2k\ge 6\) 的整数。让 \({\mathbb {F}}_q\) 表示有 q 个元素的有限域,让 V 表示维数为 n 的 \({\mathbb {F}}_q\) 上的向量空间。投影几何 \(P_q(n)\) 是由 V 的子空间组成的部分有序集;部分有序由包含给出。对于格拉斯曼图 \(J_q(n,k)\),顶点集由 V 的 k 维子空间组成。只要 \(J_q(n,k)\)的两个顶点的交集维数是\(k-1\),那么这两个顶点就是相邻的。已知图 \(J_q(n,k)\ 是距离规则的。让 \(\partial \) 表示 \(J_q(n,k)\)的路径长度距离函数。在 \(J_q(n,k)\ 中选择两个顶点 x, y,使得 \(1<\partial (x,y)<k\).集合(P_q(n))包含元素(x,y,xcap y,x+y)。在我们的主要结果中,我们只使用了 \(J_q(n,k)\) 的图结构来描述 \(x\cap y\) 和 \(x+y\) 。为了实现这一结果,我们大量使用了 \(J_q(n,k)\) 的欧几里得表示法,它对应于邻接矩阵的第二大特征值。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
Using a Grassmann Graph to Recover the Underlying Projective Geometry

Let nk denote integers with \(n>2k\ge 6\). Let \({\mathbb {F}}_q\) denote a finite field with q elements, and let V denote a vector space over \({\mathbb {F}}_q\) that has dimension n. The projective geometry \(P_q(n)\) is the partially ordered set consisting of the subspaces of V; the partial order is given by inclusion. For the Grassmann graph \(J_q(n,k)\) the vertex set consists of the k-dimensional subspaces of V. Two vertices of \(J_q(n,k)\) are adjacent whenever their intersection has dimension \(k-1\). The graph \(J_q(n,k)\) is known to be distance-regular. Let \(\partial \) denote the path-length distance function of \(J_q(n,k)\). Pick two vertices xy in \(J_q(n,k)\) such that \(1<\partial (x,y)<k\). The set \(P_q(n)\) contains the elements \(x,y,x\cap y,x+y\). In our main result, we describe \(x\cap y\) and \(x+y\) using only the graph structure of \(J_q(n,k)\). To achieve this result, we make heavy use of the Euclidean representation of \(J_q(n,k)\) that corresponds to the second largest eigenvalue of the adjacency matrix.

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来源期刊
Graphs and Combinatorics
Graphs and Combinatorics 数学-数学
CiteScore
1.00
自引率
14.30%
发文量
160
审稿时长
6 months
期刊介绍: Graphs and Combinatorics is an international journal devoted to research concerning all aspects of combinatorial mathematics. In addition to original research papers, the journal also features survey articles from authors invited by the editorial board.
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