海伦-金，《现在的希波克拉底》：互联网时代的 "医学之父"（布鲁姆斯伯里古典接受研究），伦敦：布鲁姆斯伯里学术出版社，2019 年，第 272 页，ISBN 978-1350005891，85 英镑

{"title":"海伦-金，《现在的希波克拉底》：互联网时代的 \"医学之父\"（布鲁姆斯伯里古典接受研究），伦敦：布鲁姆斯伯里学术出版社，2019 年，第 272 页，ISBN 978-1350005891，85 英镑","authors":"C. Lawrence","doi":"10.1007/s12138-020-00567-y","DOIUrl":null,"url":null,"abstract":"","PeriodicalId":509372,"journal":{"name":"International Journal of the Classical Tradition","volume":"58 22","pages":"246 - 248"},"PeriodicalIF":0.0000,"publicationDate":"2020-04-30","publicationTypes":"Journal Article","fieldsOfStudy":null,"isOpenAccess":false,"openAccessPdf":"","citationCount":"0","resultStr":"{\"title\":\"Helen King, Hippocrates Now: The ‘Father of Medicine’ in the Internet Age (Bloomsbury Studies in Classical Reception), London: Bloomsbury Academic, 2019, pp. 272, ISBN 978-1350005891, £85\",\"authors\":\"C. Lawrence\",\"doi\":\"10.1007/s12138-020-00567-y\",\"DOIUrl\":null,\"url\":null,\"abstract\":\"\",\"PeriodicalId\":509372,\"journal\":{\"name\":\"International Journal of the Classical Tradition\",\"volume\":\"58 22\",\"pages\":\"246 - 248\"},\"PeriodicalIF\":0.0000,\"publicationDate\":\"2020-04-30\",\"publicationTypes\":\"Journal Article\",\"fieldsOfStudy\":null,\"isOpenAccess\":false,\"openAccessPdf\":\"\",\"citationCount\":\"0\",\"resultStr\":null,\"platform\":\"Semanticscholar\",\"paperid\":null,\"PeriodicalName\":\"International Journal of the Classical Tradition\",\"FirstCategoryId\":\"1085\",\"ListUrlMain\":\"https://doi.org/10.1007/s12138-020-00567-y\",\"RegionNum\":0,\"RegionCategory\":null,\"ArticlePicture\":[],\"TitleCN\":null,\"AbstractTextCN\":null,\"PMCID\":null,\"EPubDate\":\"\",\"PubModel\":\"\",\"JCR\":\"\",\"JCRName\":\"\",\"Score\":null,\"Total\":0}","platform":"Semanticscholar","paperid":null,"PeriodicalName":"International Journal of the Classical Tradition","FirstCategoryId":"1085","ListUrlMain":"https://doi.org/10.1007/s12138-020-00567-y","RegionNum":0,"RegionCategory":null,"ArticlePicture":[],"TitleCN":null,"AbstractTextCN":null,"PMCID":null,"EPubDate":"","PubModel":"","JCR":"","JCRName":"","Score":null,"Total":0}