通过轴对称三维纳维-斯托克斯方程的速度先验约束论能量相等

Jiaqi Yang
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引用次数: 0

摘要

本文关注三维纳维-斯托克斯方程轴对称弱解的能量相等问题。经典的辛布罗特条件说,如果纳维-斯托克斯方程的弱解 u 属于 \(L^q(0,T;L^p(\mathbb {R}^3))\) with \(\frac{1}{q}+\frac{1}{p}=\frac{1}{2}\) and\(p\ge 4\), 那么 u 必须满足能量相等。对于轴对称纳维-斯托克斯方程,在我们之前的论文中,我们发现施加申布罗特条件(\tilde{u}=u^re_r+u^z e_z)就足够了。最近的论文(Chiun-Chuan 等,Commun PDE 34(1-3):203-232,2009;Koch 等,Acta Math 203(1):83-105,2009)告诉我们,如果 $$\begin{aligned}|\tilde{u}|le \frac{1}{r}\, \quad 0< r\le 1\,, \end{aligned}$$(0.1)then u is smooth , therefore the energy equality holds.我们自然会问速度的先验约束与能量守恒之间的关系。本文旨在研究这一问题。我们将证明,如果 $$\begin{aligned}|tilde{u}|le \frac{1}{r^d}\, \quad 0< r\le 1\, \quad d>1\,, \end{aligned}$$(0.2)和 $$\begin{aligned}\in L^{frac{6d-4}{2d-1}}(0,T;L^{2}(\mathbb {R}^3))\,,\end{aligned}$(0.3)then the energy equality holds.
本文章由计算机程序翻译,如有差异,请以英文原文为准。
On the Energy Equality via a Priori Bound on the Velocity for Axisymmetric 3D Navier–Stokes Equations

In this paper, we are concerned with the energy equality for axisymmetric weak solutions of the 3D Navier–Stokes equations. The classical Shinbrot condition says that if the weak solution u of the Navier–Stokes equations belongs \(L^q(0,T;L^p(\mathbb {R}^3))\) with \(\frac{1}{q}+\frac{1}{p}=\frac{1}{2}\) and \(p\ge 4\), then u must satisfy the energy equality. For the axisymmetric Navier–Stokes equations, in our previous paper, we found that it is enough to impose the Shinbrot condition to \(\tilde{u}=u^re_r+u^z e_z\). The recent papers (Chiun-Chuan et al., Commun PDE 34(1–3):203–232, 2009; Koch et al., Acta Math 203(1):83–105, 2009) tell us if

$$\begin{aligned} |\tilde{u}|\le \frac{1}{r}\,,\quad 0< r\le 1\,, \end{aligned}$$(0.1)

then u is smooth , therefore the energy equality holds. It is natural to ask the relation between a priori bound on the velocity and the energy conservation. The aim of this paper is to investigate this problem. We shall prove that if

$$\begin{aligned} |\tilde{u}|\le \frac{1}{r^d}\,,\quad 0< r\le 1\,,\quad d>1\,, \end{aligned}$$(0.2)

and

$$\begin{aligned} \nabla \tilde{u}\in L^{\frac{6d-4}{2d-1}}(0,T;L^{2}(\mathbb {R}^3))\,, \end{aligned}$$(0.3)

then the energy equality holds.

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