关于三维正交格伦鲍姆分割问题

Gerardo L. Maldonado, Edgardo Roldán-Pensado
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引用次数: 0

摘要

Gr\"unbaum 的等分问题问的是,对于 $\mathbb{R}^d$ 上的任何度量,是否总是有 $d$ 的超平面将 $\mathbb{R}^d$ 分割成 2^d$$\mu$ 相等的部分。众所周知,对于 $d\le 3$ 这个问题的答案是肯定的,而对于 $d\ge 5$ 这个问题的答案是否定的。这个问题的一个变式是要求两两平行面相互正交。众所周知,这个变式对 $d\le 2$ 有一个肯定的答案,而且有理由期待它对 $d\ge 3$ 有一个否定的答案。在本说明中,我们展示了证明这一点的措施。此外,我们还描述了一种算法,它可以检验$\mathbb{R}^3$中的$8n$集合是否可以被$3$相互正交的平面平均分割。出乎我们意料的是,在单位立方体中均匀、独立地选择一组随机的 $8$ 点,其不允许这样分割的概率似乎小于 $0.001$。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
On the orthogonal Grünbaum partition problem in dimension three
Gr\"unbaum's equipartition problem asked if for any measure on $\mathbb{R}^d$ there are always $d$ hyperplanes which divide $\mathbb{R}^d$ into $2^d$ $\mu$-equal parts. This problem is known to have a positive answer for $d\le 3$ and a negative one for $d\ge 5$. A variant of this question is to require the hyperplanes to be mutually orthogonal. This variant is known to have a positive answer for $d\le 2$ and there is reason to expect it to have a negative answer for $d\ge 3$. In this note we exhibit measures that prove this. Additionally, we describe an algorithm that checks if a set of $8n$ in $\mathbb{R}^3$ can be split evenly by $3$ mutually orthogonal planes. To our surprise, it seems the probability that a random set of $8$ points chosen uniformly and independently in the unit cube does not admit such a partition is less than $0.001$.
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