{"title":"单位球面上近优无正交对集合的凸性","authors":"Apurva Mudgal","doi":"arxiv-2403.18404","DOIUrl":null,"url":null,"abstract":"A subset $S$ of the unit sphere $\\mathbb{S}^2$ is called orthogonal-pair-free\nif and only if there do not exist two distinct points $u, v \\in S$ at distance\n$\\frac{\\pi}{2}$ from each other. Witsenhausen \\cite{witsenhausen} asked the\nfollowing question: {\\it What is the least upper bound $\\alpha_3$ on the\nLesbegue measure of any measurable orthogonal-pair-free subset of\n$\\mathbb{S}^2$?} We prove the following result in this paper: Let $\\mathcal{A}$\nbe the collection of all orthogonal-pair-free sets $S$ such that $S$ consists\nof a finite number of mutually disjoint convex sets. Then, $\\alpha_3 =\n\\limsup_{S \\in \\mathcal{A}} \\mu(S)$. Thus, if the double cap conjecture\n\\cite{kalai1} is not true, there is a set in $\\mathcal{A}$ with measure\nstrictly greater than the measure of the double cap.","PeriodicalId":501570,"journal":{"name":"arXiv - CS - Computational Geometry","volume":"7 1","pages":""},"PeriodicalIF":0.0000,"publicationDate":"2024-03-27","publicationTypes":"Journal Article","fieldsOfStudy":null,"isOpenAccess":false,"openAccessPdf":"","citationCount":"0","resultStr":"{\"title\":\"Convexity of near-optimal orthogonal-pair-free sets on the unit sphere\",\"authors\":\"Apurva Mudgal\",\"doi\":\"arxiv-2403.18404\",\"DOIUrl\":null,\"url\":null,\"abstract\":\"A subset $S$ of the unit sphere $\\\\mathbb{S}^2$ is called orthogonal-pair-free\\nif and only if there do not exist two distinct points $u, v \\\\in S$ at distance\\n$\\\\frac{\\\\pi}{2}$ from each other. Witsenhausen \\\\cite{witsenhausen} asked the\\nfollowing question: {\\\\it What is the least upper bound $\\\\alpha_3$ on the\\nLesbegue measure of any measurable orthogonal-pair-free subset of\\n$\\\\mathbb{S}^2$?} We prove the following result in this paper: Let $\\\\mathcal{A}$\\nbe the collection of all orthogonal-pair-free sets $S$ such that $S$ consists\\nof a finite number of mutually disjoint convex sets. Then, $\\\\alpha_3 =\\n\\\\limsup_{S \\\\in \\\\mathcal{A}} \\\\mu(S)$. Thus, if the double cap conjecture\\n\\\\cite{kalai1} is not true, there is a set in $\\\\mathcal{A}$ with measure\\nstrictly greater than the measure of the double cap.\",\"PeriodicalId\":501570,\"journal\":{\"name\":\"arXiv - CS - Computational Geometry\",\"volume\":\"7 1\",\"pages\":\"\"},\"PeriodicalIF\":0.0000,\"publicationDate\":\"2024-03-27\",\"publicationTypes\":\"Journal Article\",\"fieldsOfStudy\":null,\"isOpenAccess\":false,\"openAccessPdf\":\"\",\"citationCount\":\"0\",\"resultStr\":null,\"platform\":\"Semanticscholar\",\"paperid\":null,\"PeriodicalName\":\"arXiv - CS - Computational Geometry\",\"FirstCategoryId\":\"1085\",\"ListUrlMain\":\"https://doi.org/arxiv-2403.18404\",\"RegionNum\":0,\"RegionCategory\":null,\"ArticlePicture\":[],\"TitleCN\":null,\"AbstractTextCN\":null,\"PMCID\":null,\"EPubDate\":\"\",\"PubModel\":\"\",\"JCR\":\"\",\"JCRName\":\"\",\"Score\":null,\"Total\":0}","platform":"Semanticscholar","paperid":null,"PeriodicalName":"arXiv - CS - Computational Geometry","FirstCategoryId":"1085","ListUrlMain":"https://doi.org/arxiv-2403.18404","RegionNum":0,"RegionCategory":null,"ArticlePicture":[],"TitleCN":null,"AbstractTextCN":null,"PMCID":null,"EPubDate":"","PubModel":"","JCR":"","JCRName":"","Score":null,"Total":0}
Convexity of near-optimal orthogonal-pair-free sets on the unit sphere
A subset $S$ of the unit sphere $\mathbb{S}^2$ is called orthogonal-pair-free
if and only if there do not exist two distinct points $u, v \in S$ at distance
$\frac{\pi}{2}$ from each other. Witsenhausen \cite{witsenhausen} asked the
following question: {\it What is the least upper bound $\alpha_3$ on the
Lesbegue measure of any measurable orthogonal-pair-free subset of
$\mathbb{S}^2$?} We prove the following result in this paper: Let $\mathcal{A}$
be the collection of all orthogonal-pair-free sets $S$ such that $S$ consists
of a finite number of mutually disjoint convex sets. Then, $\alpha_3 =
\limsup_{S \in \mathcal{A}} \mu(S)$. Thus, if the double cap conjecture
\cite{kalai1} is not true, there is a set in $\mathcal{A}$ with measure
strictly greater than the measure of the double cap.