论 $$2^{k}p+1$ 的质初根

IF 0.6 4区 数学 Q3 MATHEMATICS
S. Filipovski
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引用次数: 0

摘要

Abstract 如果\(2p+1\)也是素数,那么素数\(p)就是索菲-热尔曼素数。如果 \(a\) modulo \(n\) 的阶是 \(\phi(n).\) ,那么与正整数 \(n>1\) 共素数的整数 \(a\) 就是 \(n\) 的一个原始根。Ramesh和Makeshwari证明了,如果(p)是(2p+1)的质初根,那么(p)就是索菲-杰曼质数。既然存在着作为\(2p+1\)的主根的素数\(p\),那么在本说明中,我们将考虑以下一般问题:对于哪些素数\(p\)和正整数\(k>1\),\(p\)是\(2^{k}p+1\)的主根?我们证明只有当 ((p,k)在 ((2,2), (3,3), (3,4), (5,4).
本文章由计算机程序翻译,如有差异,请以英文原文为准。
On Prime Primitive Roots of $$2^{k}p+1$$

Abstract

A prime \(p\) is a Sophie Germain prime if \(2p+1\) is prime as well. An integer \(a\) that is coprime to a positive integer \(n>1\) is a primitive root of \(n\) if the order of \(a\) modulo \(n\) is \(\phi(n).\) Ramesh and Makeshwari proved that, if \(p\) is a prime primitive root of \(2p+1\), then \(p\) is a Sophie Germain prime. Since there exist primes \(p\) that are primitive roots of \(2p+1\), in this note we consider the following general problem: For what primes \(p\) and positive integers \(k>1\), is \(p\) a primitive root of \(2^{k}p+1\)? We prove that it is possible only if \((p,k)\in \{(2,2), (3,3), (3,4), (5,4)\}.\)

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来源期刊
Mathematical Notes
Mathematical Notes 数学-数学
CiteScore
0.90
自引率
16.70%
发文量
179
审稿时长
24 months
期刊介绍: Mathematical Notes is a journal that publishes research papers and review articles in modern algebra, geometry and number theory, functional analysis, logic, set and measure theory, topology, probability and stochastics, differential and noncommutative geometry, operator and group theory, asymptotic and approximation methods, mathematical finance, linear and nonlinear equations, ergodic and spectral theory, operator algebras, and other related theoretical fields. It also presents rigorous results in mathematical physics.
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