维塔斯定理的扩展

N. Dergiades, Quang Hung Tran
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引用次数: 0

摘要

希腊建筑师科斯塔斯-维塔斯(Kostas Vittas)于 2006 年发表了一个关于循环四边形的优美定理([1]):定理 1(科斯塔斯-维塔斯,2006 年):如果 ABCD 是一个循环四边形,P 是两条对角线 AC 和 BD 的交点,那么三角形 PAB、PBC、PCD 和 PDA 的四条欧拉线是平行的。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
Extensions of Vittas’ Theorem
The Greek architect Kostas Vittas published in 2006 a beautiful theorem ([1]) on the cyclic quadrilateral as follows:Theorem 1 (Kostas Vittas, 2006): If ABCD is a cyclic quadrilateral with P being the intersection of two diagonals AC and BD, then the four Euler lines of the triangles PAB, PBC, PCD and PDA are concurrent.
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