关于不能碰到投注平面的那些表示基本问题,I

K. Wagner
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引用次数: 0

摘要

Γ是所有不能嵌入投影平面的有限图的集合。我们写G1∈G2,如果G2同态于G1,也就是说,如果有G2的子图G ' 2使得G1可以通过G ' 2中的边的收缩从G ' 2得到。偏序集合Γ 中所有极小图的子集称为Γ的极小基。我们用M(Γ)表示这个基。M(Γ)的每个图都称为最小图(Γ)。在之前的论文[2]中,我们确定了所有不连通的极小图和所有可被一个或两个顶点分离的极小图。因此,我们只需要考虑三连通最小图。假设在[2]的命题7中,我们在G14中省略了一个括号。在这个图中,也就是说,最上面的2必须用<2>代替。下面我们处理了两种新的情况,其中我们成功地确定了最小图:首先,我们假设G∈M(Γ)具有以下性质:(1)G(至少)是三连通的;(2)G中存在一个顶点a,使得图G/a(即必须破坏顶点a并且G的所有边都与a相关)包含拓扑K5,但不存在拓扑K3,3包含在G/a中。我们证明了M(Γ)中恰好有两个图满足(1)和(2)的定理,其中一个图是G14。另一图,用D,可以从K5获得我们让T是一个三重K5的周边边缘,通过插入一个新的顶点在每个T和边缘连接这三个新顶点通过三条边与另一个新的顶点躺在拓扑K5(参见图2),接着,我们认为non-planar图G的财产G / G的平面为每个顶点是另一篇论文[3]这些图表被称为近平面。我们的下一个问题是:是否存在不能嵌入投影平面的近平面图?我们证明了所有的近平面图都可以嵌入到射影平面中,只有一个图F例外。这个例外图F由两个不相交的K4和四条边(ai, bi), i=1,…,4组成,这些边将一个K4的顶点ai与另一个K4的顶点bi连接起来。然后我们证明这个图是Γ的最小图。因此,在确定Γ的最小基的问题中,情况仍然是可以假设:(1)在G中存在顶点a,使得G/a包含拓扑k3,3,并且(2)G是三连通的。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
Zum basisproblem der nicht in die projektive ebene einbettbaren graphen, I

Le Γ be the set of all finite graphs which are not embeddable into the projective plane. We write G1G2, if G2 is homomorphic to G1, that is, if there is a subgraph G2 of G2 such that G1 can be obtained from G2 by contraction of edges in G2. The subset of all minimal graphs in the partially ordered set Γ is called the minimal basis of Γ. We denote this basis by M(Γ). Every graph of M(Γ) is called a minimal graph (of Γ). In a former paper [2], we determined all disconnected minimal graphs and all minimal graphs separable by one or two vertices. Hence, we need only consider three-connected minimal graphs. Let us say that in our Proposition 7 of [2] we omitted a bracket in G14. In this graph, namely, the uppermost 2 must be replaced by <2>.

In the following we deal with two new cases, in which we succeed in determining the minimal graphs:

First, let us suppose that G∈M(Γ) has the properties: (1) G is (at least) three-connected and (2) there is a vertex a in G such that the graph G/a (that is, one has to destroy the vertex a and all edges of G incident to a) contains a topologic K5 but there exists no topologic K3,3 contained in G/a. We prove the theorem that there are exactly two graphs in M(Γ) satisfying (1) and (2). One of these graphs is the G14. The other graph, denoted by D, can be obtained from the K5 where we let T be a triple of neighboring edges in the K5, by inserting a new vertex on every edge of T and by then connecting these three new vertices through three edges with one further new vertex a lying outside the topologic K5 (see Figure 2).

Second, we consider non-planar graphs G with the property that G/a is planar for every vertex a of G. In another paper [3] these graphs have been called nearly planar. Our next question is: Are there nearly planar graphs not being embeddable into the projective plane? We prove the theorem that all nearly planar graphs can be embedded into the projective plane with a single exception of one graph F. This exceptional graph F consists of two disjoint K4 and four edges (ai, bi), i=1,…, 4 which join the vertices ai of the one K4 with the vertices bi of the other K4. We then show that this graph is a minimal graph of Γ. So, in the problem of determining the minimal basis of Γ, the case remains that one can assume: (1) There is a vertex a in G such that G/a contains a topologic K3,3 and (2) G is three-connected.

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