丢番图方程的整数解\(\left (1-\frac{1}{\mathit{x}}\right)\)\(\left (1-\frac{1}{\mathit{y}}\right)\)\(\left (1-\frac{1}{\mathit{z}}\right)\) = \(\frac{1}{\mathit{l}}\)

Asian Research Journal of Mathematics Pub Date : 2023-11-07 DOI:10.9734/arjom/2023/v19i11758

Qiang Wang, Qingwei Tu

引用次数: 0

摘要

本文主要寻找整数变量(\(\mathit{x}\), \(\mathit{y}\), \(\mathit{z}\), \(\mathit{l}\))的丢番图方程\(\left (1-\frac{1}{\mathit{x}}\right)\)\(\left (1-\frac{1}{\mathit{y}}\right)\)\(\left (1-\frac{1}{\mathit{z}}\right)\) = \(\frac{1}{\mathit{l}}\)的所有解。

本文章由计算机程序翻译，如有差异，请以英文原文为准。

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Integer Solutions of the Diophantine Equation \(\left (1-\frac{1}{\mathit{x}}\right)\) \(\left (1-\frac{1}{\mathit{y}}\right)\) \(\left (1-\frac{1}{\mathit{z}}\right)\) = \(\frac{1}{\mathit{l}}\)

In this paper, we mainly find all solutions of the diophantine equation \(\left (1-\frac{1}{\mathit{x}}\right)\) \(\left (1-\frac{1}{\mathit{y}}\right)\) \(\left (1-\frac{1}{\mathit{z}}\right)\) = \(\frac{1}{\mathit{l}}\) in integer variables (\(\mathit{x}\), \(\mathit{y}\), \(\mathit{z}\), \(\mathit{l}\) ).

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Asian Research Journal of Mathematics

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