无横切直角Artin群的测度等价分类

Camille Horbez, Jingyin Huang
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引用次数: 11

摘要

证明了如果两个无横切直角Artin群是测度等价的,则它们具有同构的可拓图。因此,当且仅当两个具有有限外自同构群的直角Artin群同构时,它们是测度等价的。这符合准等距分类。然而,与准等距问题相反,我们观察到直角Artin群在最强可能意义上没有超刚性,原因有二。首先,一个直角Artin群$G$总是度量等价于同一定义图上任意无限可数可服从群的图积。其次,当$G$是非阿贝时,$G$的Salvetti复的全称覆盖的自同构群总是包含无限生成的(非一致)格。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
Measure equivalence classification of transvection-free right-angled Artin groups
We prove that if two transvection-free right-angled Artin groups are measure equivalent, then they have isomorphic extension graphs. As a consequence, two right-angled Artin groups with finite outer automorphism groups are measure equivalent if and only if they are isomorphic. This matches the quasi-isometry classification. However, in contrast with the quasi-isometry question, we observe that no right-angled Artin group is superrigid in the strongest possible sense, for two reasons. First, a right-angled Artin group $G$ is always measure equivalent to any graph product of infinite countable amenable groups over the same defining graph. Second, when $G$ is nonabelian, the automorphism group of the universal cover of the Salvetti complex of $G$ always contains infinitely generated (non-uniform) lattices.
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