决策树:新旧结果

R. Fleischer
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引用次数: 10

摘要

本文证明了用于检验由线性不等式定义的集S≤R n中的隶属性的代数决策树的两个一般下界。设秩(S)为包含在S闭包中的线性子空间的最大维数(在欧氏拓扑中)。首先,我们证明了任何使用线性函数(我们称这种函数为mlf-函数)乘积的S决策树的深度必须至少为n - rank(S)。这解决了a.c. Yao提出的一个开放性问题,并且可以用来表明,在计算n个元素中最大的k时,mlf函数并不比输入变量之间的简单比较更强大。姚在最多允许两个线性函数积的特殊情况下证明了这个结果。我们的证明还表明,该问题的任何决策树都必须具有指数大小。使用同样的方法,我们可以给出Rabin定理的另一种证明,即使用任意解析函数的S的任何决策树的深度至少为n−rank(S)。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
Decision trees: old and new results
Abstract In this paper, we prove two general lower bounds for algebraic decision trees which test membership in a set S ⊆ R n which is defined by linear inequalities. Let rank( S ) be the maximal dimension of a linear sub- space contained in the closure of S (in Euclidean topology). First we show that any decision tree for S which uses products of linear functions (we call such functions mlf- functions ) must have depth at least n −rank( S ). This solves an open question raised by A. C. Yao and can be used to show that mlf-functions are not really more powerful than simple comparisons between the input variables when computing the largest k out of n elements. Yao proved this result in the special case when products of at most two linear functions are allowed. Our proof also shows that any decision tree for this problem must have exponential size. Using the same methods, we can give an alternative proof of Rabin's theorem, namely that the depth of any decision tree for S using arbitrary analytic functions is at least n −rank( S ).
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