快速返回R-S-S-R机构的设计

F. O. Suareo, K. C. Gupta
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引用次数: 4

摘要

提出了一种合成满足给定时间比和从动件振荡角要求的快速返回R-S-S-R机构的代数方法。在这些设计中,定义从动件球面关节的三个参数满足二次条件。当输入和输出轴之间的轴角为零时,该二次条件化为平面情况下常见的经典结果圆方程。快速返回R-S-S-R连杆机构的求解空间为:对于每一组曲柄长度a 2、从动件轴向距离s4、初始从动件角φ0的选择,有4组从动件长度a 4、初始曲柄角θ0、曲柄轴向距离s2、联轴器长度a 3。对这些设计进行筛选,使它们没有分支缺陷,传输角值在给定范围内,并且具有合理的链路长度比例。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
Design of Quick-Returning R-S-S-R Mechanisms
An algebraic method is presented to synthesize quick-returning R-S-S-R mechanisms which satisfy the given time-ratio and follower oscillation angle requirements. In these designs, the three parameters, which define the follower spheric joint, satisfy a quadratic condition. When the shaft angle between the input and output shafts is zero, this quadratic condition reduces to the equation of a circle which is a familiar classical result for the planar case. The solution space for the quick-returning R-S-S-R linkage is such that, for each set of choices for crank length a 2 , follower axial distance S 4 , and initial follower angle φ0 , there are four sets of follower length a 4 , initial crank angle θ0 , crank axial distance S 2 , and coupler length a 3 . These designs are screened so that they do not have branch defect, have transmission angle values in a given range, and have reasonable link length proportions.
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