两个环形表面的交点

Hee-Seok Heo, S. Hong, Myung-Soo Kim, G. Elber
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引用次数: 1

摘要

给出了一种计算两个环形曲面相交曲线的高效鲁棒算法,每个曲面都是由一个运动圆产生的扫描/spl杯//sub /C/sup /。给定两个环形曲面/spl cup//sub u/C/sub 1//sup u/和/spl cup//sub v/C/sub 2//sup v/,我们将条件C/sub 1//sup u//spl cap/C/sub 2//sup v//spl ne/O(即两个圆C/sub 1//sup u/和C/sub 2//sup v/的交点非空)表示为一个较低阶的二元方程/spl λ /(u,v)= 0。除了一些冗余解和退化情况外,/spl λ /(u,v)=0的每个解到交点C/sub 1//sup u//spl cap/C/sub 2//sup v/都有一个有理映射。因此,一旦我们计算了/spl λ /(u,v)=0的零集,构造相交曲线就很简单了。对一些特殊情况进行了分析,并考虑了如何构造相应的交点曲线。
本文章由计算机程序翻译,如有差异,请以英文原文为准。
The intersection of two ringed surfaces
Presents an efficient and robust algorithm to compute the intersection curve of two ringed surfaces, each being the sweep /spl cup//sub u/C/sup u/ generated by a moving circle. Given two ringed surfaces /spl cup//sub u/C/sub 1//sup u/ and /spl cup//sub v/C/sub 2//sup v/, we formulate the condition C/sub 1//sup u//spl cap/C/sub 2//sup v//spl ne/O (i.e. that the intersection of the two circles C/sub 1//sup u/ and C/sub 2//sup v/ is non-empty) as a bivariate equation /spl lambda/(u,v)= 0 of relatively low degree. Except for some redundant solutions and degenerate cases, there is a rational map from each solution of /spl lambda/(u,v)=0 to the intersection point C/sub 1//sup u//spl cap/C/sub 2//sup v/. Thus, it is trivial to construct the intersection curve once we have computed the zero-set of /spl lambda/(u,v)=0. We also analyze some exceptional cases and consider how to construct the corresponding intersection curves.
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